a0.calculus

This class was created by Brainscape user Ho Jim. Visit their profile to learn more about the creator.

Decks in this class (15)

Limit && Countinuity
重要极限,
常见等价,
2 4
17  cards
导数 && 微分
连续性、可导性、可微性的关系,
可导性证明,
常见函数导数
17  cards
求解不定积分
Cos x,
Cos x,
Cos x
37  cards
定积分
定积分的规定,
定积分的几何意义,
函数可积的条件
26  cards
微积分的几何应用
求平面图形围成内的面积,
极坐标图形围成面积的计算方法,
1
16  cards
微分方程
一阶线性可分离变量型方程的解法,
一阶线性可分离变量型方程的例题,
一阶线性*齐次*方程
15  cards
函数图像描述、定理、泰勒公式
有界定理,
零点定理条件跟结论是什么?,
介值定理条件跟结论是什么?
8  cards
反常积分
反常积分:无穷限积分的计算方法,
反常积分:暇积分的计算方法,
反常积分中的重要结论
3  cards
向量与坐标系、数量积、向量积、平面&直线方程
方向角,
单位化向量,
投影的运算性质:
52  cards
曲面,空间曲线,空间直线
求**旋转曲面方程**的技巧,
X z,
单叶双曲面形成的图形
29  cards
多元函数
如何证明多元函数极限不存在,
多元函数计算极限方法:简单变换(有根号就通分),
多元函数计算极限方法:等价无穷小替换
85  cards
多元积分
二重积分的符号,
例题 : 计算二重积分,
例题 :交换二次积分顺序
36  cards
曲线积分
Hint 1,
第一类线性积分列式的三种情况是什么?,
第一类线性积分的普通对称性是什么?
23  cards
无穷级数
收敛的必要条件是什么? 收敛必要条件的逆否命题是什么?,
P p,
级数收敛的判断 (利用重要级数,知道判断的理由)
11  cards
期末复习
正项级数的比较法是什么?,
正项级数的敛散性判断的比值法和根式法是什么?
2  cards

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a0.calculus

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