How can you calculate the horizontal distance travelled
Horizontal velocity X time of flight
State the 4 equations of motion
V= U+at
S= 1/2(u+v)t
S=ut + 1/2at^2
V^2=U^2 + 2as
When is the range at its maximum value?
When the angle of projection is at 45
The range when projected at an angle is the same as for a particle projected at an angle (90-angle)
Therefore a particle projected at 30 degrees has the same range as one projected at 60 degrees