22: Electrolysis Flashcards

(48 cards)

1
Q

Explain the meaning of electrolysis.

A

Electrolysis is the process of decomposing an electrolyte with an electric current.

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2
Q

Name the apparatus in which electrolysis is carried out.

A

Electrolytic cell

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3
Q

State and explain the polarity of the cathode in an electrolytic cell.

A

At the cathode, reduction reactions occur, which means the cations gain electrons from the electrode. As the cations are attracted to the electrode, the polarity of the cathode in an electrolytic cell is negative.

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4
Q

State and explain the polarity of the anode in an electrolytic cell.

A

At the anode, oxidation occurs, which means the anions lose electrons to the electrode. As the anions are attracted to the electrode, the polarity of the anode in an electrolytic cell is positive.

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5
Q

State and explain whether the positive electrode is the cathode or the anode in an electrolytic cell.

A

At the positive electrode, anions are attracted; they lose electrons and are oxidised. Hence the positive electrode of the electrolytic cell is the anode.

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6
Q

State and explain whether the negative electrode is the cathode or the anode in an electrolytic cell.

A

At the negative electrode, cations are attracted; they gain electrons and are reduced. Hence the negative electrode of the electrolytic cell is the cathode.

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7
Q

State and explain the polarity of the cathode in an electrochemical cell.

A

At the cathode, reduction occurs, so the electrode gains electrons from the external circuit. As the electrons in the external circuit are attracted to the cathode, the polarity of the cathode in the chemical cell is positive.

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8
Q

State and explain the polarity of the anode in an electrochemical cell.

A

At the anode, oxidation occurs, so the electrode loses electrons and releases them into the external circuit. As the electrons flow from the anode to the positive terminal in the external circuit, the polarity of the anode in the chemical cell is negative.

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9
Q

State and explain whether the positive electrode is the cathode or the anode in an electrochemical cell.

A

At the positive electrode, electrons are received from the external circuit to reduce the oxidising agent. Hence the positive electrode of the chemical cell is the cathode.

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10
Q

State and explain whether the negative electrode is the cathode or the anode in an electrochemical cell.

A

At the negative electrode, electrons are released into the external circuit and the reducing agent is oxidised. Hence the negative electrode of the chemical cell is the anode.

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11
Q

Explain why aqueous solutions of electrolytes contain more than one type of cation and more than one type of anion.

A

There are hydrogen ions and hydroxide ions which arise from the dissociation of water.

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12
Q

Explain why the electrolysis of water uses acidified water.

A

Pure water is a poor conductor of electricity. Adding a small amount of sulphuric acid can improve the conductivity of water.

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13
Q

Name an apparatus to demonstrate the electrolysis of acidified water.

A

Hoffman voltameter

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14
Q

Explain why no sulphur compounds are produced in the electrolysis of water (acidified with sulphuric acid).

A

The sulphur in the sulphuric acid exists as sulphate ions, which is very low in the electrochemical series / a very weak reducing agent. Meanwhile, hydroxide ion is a stronger reducing agent than sulphate ion and it is preferentially discharged at the positive electrode. Hence sulphate ions remain as ions in the solution and do not produce sulphur compounds in electrolysis of water.

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15
Q

Acidified water is electrolysed. Describe how the product at the cathode can be tested.

A

Hydrogen gas is liberated at the cathode. It burns with a “pop” sound when a burning splint is inserted into it.

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16
Q

Write the ionic equation at the cathode of the electrolysis of acidified water.

A

2H+ + 2e- -> H2

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17
Q

Write the ionic equation at the anode of the electrolysis of acidified water.

A

4OH- -> 2H2O + O2 + 4e-

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18
Q

Explain the ratio between the theoretical amounts of hydrogen gas and oxygen gas produced in the electrolysis of water.

A

When 4 electrons are gained in the cathode, 2 hydrogen gas molecules are formed. When 4 electrons are released in the anode, only 1 oxygen gas molecule is formed. Since electrons are released from the anode at the same rate as they are gained in the cathode, the volume ratio of hydrogen to oxygen is 2:1.

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19
Q

Explain two reasons why the actual volume of oxygen gas collected is much smaller than that of hydrogen gas collected in the electrolysis of water.

A
  1. The produced volume ratio of hydrogen to oxygen is 2:1.
  2. Some oxygen dissolves in the water while hydrogen cannot dissolve in water.
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20
Q

Very dilute sodium chloride solution (0.01M) is electrolysed with a few drops of universal indicator solution.
State the colour changes at the cathode and anode after a period of time.

A

Cathode: The universal indicator solution changes from green to blue.
Anode: The universal indicator solution changes from green to red.

21
Q

Very dilute sodium chloride solution (0.01M) is electrolysed with a few drops of universal indicator solution.
Explain the colour change at the cathode.

A

At the cathode, hydrogen ions are preferentially discharged. As electrolysis proceeds, water molecules dissociate to replace the hydrogen ions, but the hydroxide ions are not consumed and accumulate. Thus, the concentration of hydroxide ions rises above that of hydrogen ions, the solution there becomes alkaline, and the indicator changes from green to blue.

22
Q

Very dilute sodium chloride solution (0.01M) is electrolysed with a few drops of universal indicator solution.
Explain the colour change at the anode.

A

At the anode, hydroxide ions are preferentially discharged. As electrolysis proceeds, water molecules dissociate to replace the hydroxide ions, but the hydrogen ions are not consumed and accumulate. Thus, the concentration of hydrogen ions rises above that of hydroxide ions, the solution there becomes acidic, and the indicator changes from green to red.

23
Q

Very dilute sodium chloride solution (0.01M) is electrolysed with a few drops of universal indicator solution.
Explain any change in concentration of sodium chloride.

A

The concentration of the sodium chloride increases since water is consumed in the electrolysis.

24
Q

Very dilute sodium chloride solution (0.01M) is electrolysed.
Name all products after complete reaction.

A

Hydrogen gas, oxygen gas, more concentrated sodium chloride solution

25
Concentrated sodium chloride solution (2M) is electrolysed. Name all products after complete reaction.
Hydrogen gas, chlorine gas, sodium hydroxide solution
26
Concentrated sodium chloride solution (2M) is electrolysed with a few drops of universal indicator solution. Explain the colour change of the solution.
Hydrogen ions and chloride ions are preferentially discharged. At the cathode, hydrogen ions are consumed. Water molecules dissociate to replace the hydrogen ions, but the hydroxide ions are not consumed and **accumulate**. Thus, the concentration of hydroxide ions rises above that of hydrogen ions, the solution there becomes **alkaline**, and the indicator changes from green to blue.
27
Concentrated sodium chloride solution (2M) is electrolysed. Describe a chemical test and expected result for the gas liberated at the cathode.
Hydrogen gas is liberated at the cathode. It burns with a "pop" sound when a burning splint is inserted into it.
28
Concentrated sodium chloride solution (2M) is electrolysed. Describe a chemical test and expected result for the gas liberated at the anode.
Chlorine gas is liberated at the anode. When a **moist blue litmus** paper is held near it, the paper turns to red immediately and is slowly **bleached** to white colour.
29
Explain the colour change when a moist blue litmus paper is held over chlorine gas.
Chlorine gas reacts with the water on the litmus paper to produce HCl (hydrochloric acid) and HOCl (hypochlorous acid). The hydrochloric acid immediately reacts with the litmus paper and changes it to **red**. The hypochlorous acid acts as **bleaching agent** and slowly bleaches the litmus paper to white.
30
Name the ion responsible for bleaching in aqueous chlorine solution.
Hypochlorite ion (OCl-), which can bleach by oxidation.
31
Concentrated sodium chloride solution (2M) is electrolysed to obtain hydrogen gas. Name one suitable electrode and one unsuitable electrode for the reaction.
Suitable electrode: graphite Unsuitable electrode: platinum, since it is **attacked** by chlorine.
32
Dilute copper(II) sulphate solution is electrolysed with carbon electrodes. State 3 expected observations.
1. The cathode is coated with a reddish brown solid. 2. A colourless gas is produced at the anode. 3. The blue colour of the solution fades.
33
Dilute copper(II) sulphate solution is electrolysed with carbon electrodes. Name all products after complete reaction.
Oxygen gas, copper solid, sulphuric acid.
34
Dilute copper(II) sulphate solution is electrolysed. Name and explain the material of electrode(s) which allows the colour intensity of the solution to be unchanged.
**Copper anode**. Copper is a stronger reducing agent than hydroxide ions and sulphate ions. Therefore, it **dissolves** to form copper(II) ions. Meanwhile, copper(II) ions are reduced into copper metal at the cathode at the same rate. The concentration of blue copper(II) ions remains the same so the colour intensity of the solution is unchanged.
35
Dilute copper(II) sulphate solution is electrolysed. Name and explain the material of electrode(s) which allows the pH of the solution to be unchanged.
Copper or any metal higher than copper in the electrochemical series is used as **anode**. These reactive metals are stronger reducing agents than hydroxide ions and sulphate ions. Therefore, they are oxidised to form metal ions and hydroxide ions are **not discharged**. Copper(II) ions are reduced in the cathode and the reactive metal is oxidised in the anode. There is **no net change** in the concentration of hydrogen or hydroxide ions, so the pH of the solution is unchanged.
36
Concentrated sodium chloride solution (2M) is electrolysed. Name the material of the electrode(s) which allows the discharging of metal ions instead of hydrogen ions.
Mercury cathode, it discharges the sodium ions and forms an **amalgam** with it.
37
Name one device in the industry which uses mercury cathode in electrolysis.
Flowing mercury electrolytic cell
38
Rank the reducing powers of hydroxide ion, halide ions, nitrate ion, and sulphate ion from high to low.
Highest: Hydroxide ion, **iodide ion**. bromide ion, **chloride ion**, nitrate ion, sulphate ion (lowest)
39
Rank the oxidising powers of calcium ion, sodium ion, lead ion, copper ion, and hydrogen ion from high to low.
Highest: copper ion, **hydrogen ion**, lead ion, sodium ion, calcium ion (lowest)
40
List 3 criteria for determining the preferential discharge of ions during electrolysis.
1. Position in electrochemical series. 2. Concentration of ions with similar position in the solution. 3. Presence of special electrodes (reactive metal anode or mercury cathode).
41
Name 4 common metals for electroplating.
Copper, chromium, silver, tin
42
Name the anode, cathode, and electrolyte in metal plating.
Anode: plating metal Cathode: object to be plated Electrolyte: solution with ions of the plating metal
43
Name the anode, cathode, and electrolyte in aluminium anodisation.
Anode: Aluminium metal (to be anodised) Cathode: platinum Electrolyte: dilute sulphuric acid
44
Explain the principle of aluminium anodisation using preferential discharge.
At the anode, **hydroxide ions** are discharged to oxygen, reacting with aluminium to form an aluminium oxide layer. Although aluminium is higher in the electrochemical series than hydroxide ions, its discharge creates an **insoluble aluminium hydroxide** layer which prevents aluminium from further discharging.
45
List 5 requirements to obtain a good metal coating during electroplating.
1. The object must be clean and free of grease. 2. The object should be rotated for an even coating. 3. The current must not be too large of the coating will flake off. 4. The temperature of the electrolyte must be controlled for the rate of coating deposit. 5. The concentration of the electrolyte must be controlled for the rate of coating deposit.
46
Name 3 major pollutants in the electroplating industry.
Acids and alkalis, heavy metal ions, cyanides
47
List 7 ways to control pollution from the electroplating industry.
1. Design better rinsing systems and reduce water usage. 2. Replace cyanides with less toxic compounds. 3. Recover metals from waste solutions. 4. Reuse plating bath solutions and rinsing water. 5. Adjust pH of effluents to around neutral. 6. Remove heavy metal ions in waste water by precipitation using sodium hydroxide. 7. Remove chromium(IV) ions in waste water.
48
Describe the process of removing chromium(IV) ions in waste water.
1. Reduce them to less toxic chromium(III) ions using a reducing agent (eg. sodium sulphite). 2. Add sodium hydroxide solution to precipitate the ions as **chromium(III) hydroxide**.