Precedence Law
AB = A.B
A.B + C = (A.B) + C
A + B.C = A + (B.C)
DeMorgan’s Theorem
'Break the line, change the sign' \_\_\_\_ \_\_ \_\_ (A.B) = A + B //Nand Gate \_\_\_\_ (A+B) = A̅ . B̅ //Nor Gate \_\_\_\_ (A̅ . B̅) = A + B \_\_\_\_ (A̅ + B̅) = A . B
Distributive Law
A.(B+C) = (A.B) + (A.C) A+(B.C) = (A+B).(A+C)
Associative Law
(A.B).C = A.(B.C) = A.B.C (A+B)+C = A+(B+C) = A+B+C
Commutative Law
A.B = B.A A+B = B+A
A.1
= A
A.0
= 0
A+1
= 1
A+0
= A
Absorption Law
X + X . Y = X Proof: X + X . Y = X . 1 + X . Y //X is equal to X . 1 = X . (Y + 1) //Distributive Law = X . 1 //Y or 1 is equal to 1 = X