chain rule
• The chain rule states that if f(x) = g(h(x)), where g and h are differentiable functions, then f is differentiable and
f’(x)=g’(h(x))*h’(x).
- Some functions are actually combinations of other functions, such as products or quotients. To differentiate these functions, it may be necessary to use several computational techniques and to use some more than once.
note
Find dy/dx:y=(2x+1)^2(3x)^2.
dy/dx=(2x+1)^2(18x)+(3x)^2(8x+4)
Find dy/dx, where y=(x+5)^3(x−3)^3
d/ydx=−24(x+5)^2 / (x−3)^4
A particle’s position is given by the function x(t)=(4−t)^3.What is the value of dx/dt when t=3?
dx/dt=−3
Given y=4x^3 / 3, find dy/dx.
dydx=4x^2
Find dy/dx given that y=3u^2,u=2v,and v=x/6.
dy/dx=2x/3
Given y=(3x^2+7x)^3, find dy/dx.
dy/dx=3(3x^2+7x)^2(6x+7)
Given P=−3t^2+6t, find dP/dt.
dP/dt=−6t+6
If h=3k^2 and k=(3t)^2, then find dh/dt
dh/dt=972t^3
Given y=(x^2+3x)^3(2x^2−4x)^2,find dy/dx.
dy/dx=2(x2+3x)^3(2x^2−4x) (4x−4) + 3(2x^2−4x)^2(x^2+3x)^2(2x+3).
Given y=2x^2, find dy/dx
dy/dx=4x
Find dy/dx given that y=3u^2/3+2u^−1/2, and u=x^2.
dy/dx=4x^1/3−2x^−2
Given y=(2x+1)^2/ 3x^2, find dy/dx.
dy/dx=3x^2⋅4(2x+1)−(2x+1)^2⋅6x / (3x^2)^2