Acceleration

Question 1

Q1 → What is acceleration?
A → Acceleration is the rate at which an object changes its velocity. It is also described as the rate of change of velocity, meaning it tells us how much the velocity changes per unit time.

Q2 → What does “rate of change of velocity” mean?
A → It means the amount that velocity changes per unit time. In other words, acceleration measures how much an object’s velocity increases or decreases every second.

Q3 → Is acceleration a scalar or vector quantity? Explain.
A → Acceleration is a vector quantity. This means it has both magnitude (size) and direction. Because velocity is a vector (it includes direction), any change in velocity also includes direction, so acceleration must also include direction.

Q4 → What are the units of acceleration?
A → Acceleration is measured in metres per second squared (m/s²). This unit shows how many metres per second the velocity changes every second.

Q5 → What does it mean if acceleration is positive?
A → If the value of acceleration is positive, the object is getting faster. This means its velocity is increasing in the chosen direction, and the object is accelerating.

Q6 → What does it mean if acceleration is negative?
A → If the value of acceleration is negative, the object is getting slower. This is called deceleration. When an object is slowing down, it is decelerating and its acceleration has a negative value.

Q7 → What is meant by deceleration?
A → Deceleration is when an object is slowing down. It occurs when acceleration has a negative value, meaning the velocity is decreasing over time.

Q8 → What is the equation for calculating change in velocity?
A → Change in velocity is calculated using the equation:
change in velocity = final velocity − initial velocity
In shorthand form:
∆v = v − u

Q9 → What do the symbols ∆v, v, and u represent in the change in velocity equation?
A → ∆v represents the change in velocity, measured in metres per second (m/s).
v represents the final velocity, measured in metres per second (m/s).
u represents the initial velocity, measured in metres per second (m/s).

Q10 → What is average acceleration?
A → Average acceleration is the total change in velocity divided by the time taken for that change to occur. It tells us how much the velocity changes per second over a given time period.

Q11 → What is the formula for average acceleration?
A → Acceleration (m/s²) = Change in Velocity (m/s) ÷ Time (s)
In shorthand form:
a = Δv / t

Q12 → What do the symbols in the average acceleration equation represent?
A → In the equation a = Δv / t:

• a (or α) is the acceleration, measured in metres per second squared (m/s²).
• Δv is the change in velocity, measured in metres per second (m/s).
• t is the time taken for the change, measured in seconds (s).

Q13 → What does uniform acceleration mean?
A → Uniform acceleration means constant acceleration. This means the acceleration does not change over time and the velocity changes by equal amounts in equal time intervals.

Q14 → What is another name for constant acceleration?
A → Constant acceleration is sometimes called uniform acceleration.

Q15 → What equation links final velocity, initial velocity, acceleration, and distance for uniform acceleration?
A → For objects in uniform acceleration, the equation is:
(final velocity)² − (initial velocity)² = 2 × acceleration × distance
In shorthand form:
v² − u² = 2as

Q16 → What do the symbols in the equation v² − u² = 2as represent?
A → In the equation v² − u² = 2as:

• v is the final velocity, measured in metres per second (m/s).
• u is the initial velocity, measured in metres per second (m/s).
• a is the acceleration, measured in metres per second squared (m/s²).
• s is the distance travelled or displacement, measured in metres (m).

Q17 → What does displacement (s) mean in the equation v² − u² = 2as?
A → Displacement is the distance travelled in a specific direction. It is measured in metres (m). In this equation, s represents displacement, which includes direction as it is linked to velocity and acceleration.

Q18 → How can the uniform acceleration equation be rearranged to calculate final velocity?
A → Starting from:
v² − u² = 2as

Rearrange to:
v² = u² + 2as

Then take the square root to find v:
v = √(u² + 2as)

Q19 → How can the uniform acceleration equation be rearranged to calculate acceleration?
A → Starting from:
v² − u² = 2as

Rearrange to make a the subject:
a = (v² − u²) / 2s

This can be used if the initial velocity, final velocity, and displacement are known.

Q20 → How can the uniform acceleration equation be rearranged to calculate initial velocity?
A → Starting from:
v² − u² = 2as

Rearrange to:
u² = v² − 2as

Then take the square root to find u if required.

Q21 → How can the uniform acceleration equation be rearranged to calculate displacement?
A → Starting from:
v² − u² = 2as

Rearrange to make s the subject:
s = (v² − u²) / 2a

This can be used if the initial velocity, final velocity, and acceleration are known.

Q22 → What is acceleration due to gravity?
A → Acceleration due to gravity (g) is the uniform acceleration experienced by objects in free fall near the Earth’s surface. It has a value of approximately 9.8 m/s².

Q23 → Why is acceleration due to gravity described as uniform?
A → Acceleration due to gravity is described as uniform because it is constant for objects in free fall near the Earth’s surface. This means the acceleration does not change as the object falls.

Q24 → How is acceleration due to gravity related to gravitational field strength?
A → Near the Earth’s surface, the value of acceleration due to gravity (g), which is approximately 9.8 m/s², has the same value as the gravitational field strength.

Answer 1

Source 1: Acceleration:
ACCELERATION is the rate at which an object changes its velocity.

It is a VECTOR quantity, which means it includes both magnitude and DIRECTION.

If the value of ACCELERATION is POSTIVE, the object is getting FASTER (accelerating).

If the value of ACCELERATION is NEGATIVE, the object is getting SLOWER (decelerating).

Average Acceleration:
To find average acceleration, we use the equation: Acceleration (m/s²) = Change in Velocity (m/s) / Time (s)
(shorthand form: a = ΔV / t),
Where:

Δv is the change in VELOCITY in Metres per second (m/s).
t is the TIME taken for this change in Seconds) (s).
a is the ACCELERATION in Metres per second squared (m/s²). ||| Uniform Acceleration:
For uniform acceleration, the following equation can be used: (Final Velocity)² - (Initial Velocity)² = 2 x Acceleration x Distance
(shorthand form: v² - u² = 2as), Where:
v is the FINAL VELOCITY (m/s).
u is the INITIAL VELOCITY (m/s).
a is the ACCELERATION (m/s²).
s is the DISTANCE travelled (m). ////////// Source 2: Acceleration:

Acceleration (The rate of change in speed (or velocity) is measured in metres per second squared) is the rate of change of velocity. It is the amount that velocity changes per unit time.

The change in velocity can be calculated using the equation:

change in velocity = final velocity - initial velocity (shorthand form: ∆v = v - u). ||| The average acceleration of an object can be calculated using the equation: Acceleration (m/s²) = Change in Velocity (m/s) / Time (s)
(shorthand form: a = ΔV / t), This is when:

acceleration (α) is measured in metres per second squared (m/s²)
change in velocity (∆v) is measured in metres per second (m/s)
time taken (t) is measured in seconds (s)
If an object is slowing down, it is decelerating (and its acceleration has a negative value). ||| Velocity, acceleration and distance
This equation applies to objects in uniform acceleration:

(final velocity)2 - (initial velocity)2 = 2 × acceleration × distance (shorthand form: v² - u² = 2as), This is when:

final velocity (v) is measured in metres per second (m/s)
initial velocity (u) is measured in metres per second (m/s)
acceleration (a) is measured in metres per second squared (m/s2)
displacement (s) is measured in metres (m) ||| Calculating final velocity:
The equation above can be used to calculate the final velocity of an object if its initial velocity, acceleration and displacement are known. To do this, rearrange the equation to find v: v² = u² + 2 a s
v = √ (u² + 2as) ||| Calculating acceleration:
The equation can also be used to calculate the acceleration of an object if its initial and final velocities, and the displacement are known. To do this, rearrange the equation to find a: v² - u² = 2 a s
a = (v² - u²) / 2s ||| Calculating other quantities:
The equation can also be rearranged to find initial velocity (u) and displacement (s): u² = v² - 2 a s
s = (v² - u²) / 2a ////////// Source 3: Uniform Acceleration Means a Constant Acceleration:
1) Constant acceleration is sometimes called uniform acceleration.
2) Acceleration due to gravity (g) is uniform for objects in free fall. It’s roughly equal to 9.8 m/s2
hear the Earth’s surface and has the same value as gravitational field strength.

Question 2

Q1 → What is acceleration?

Question 3

A → Acceleration is the rate at which an object changes its velocity. It is also described as the rate of change of velocity

Answer 3

meaning it tells us how much the velocity changes per unit time.

Question 5

Q2 → What does “rate of change of velocity” mean?

Question 6

A → It means the amount that velocity changes per unit time. In other words

Answer 6

acceleration measures how much an object’s velocity increases or decreases every second.

Question 8

Q3 → Is acceleration a scalar or vector quantity? Explain.

Question 9

A → Acceleration is a vector quantity. This means it has both magnitude (size) and direction. Because velocity is a vector (it includes direction)

Answer 9

any change in velocity also includes direction

Question 11

Q4 → What are the units of acceleration?

Question 12

A → Acceleration is measured in metres per second squared (m/s²). This unit shows how many metres per second the velocity changes every second.

Question 14

Q5 → What does it mean if acceleration is positive?

Question 15

A → If the value of acceleration is positive

Answer 15

the object is getting faster. This means its velocity is increasing in the chosen direction

Question 17

Q6 → What does it mean if acceleration is negative?

Question 18

A → If the value of acceleration is negative

Answer 18

the object is getting slower. This is called deceleration. When an object is slowing down

Question 20

Q7 → What is meant by deceleration?

Question 21

A → Deceleration is when an object is slowing down. It occurs when acceleration has a negative value

Answer 21

meaning the velocity is decreasing over time.

Question 23

Q8 → What is the equation for calculating change in velocity?

Question 24

A → Change in velocity is calculated using the equation:

Question 25

change in velocity = final velocity − initial velocity

Question 26

In shorthand form:

Question 27

∆v = v − u

Question 28

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Question 29

**Q9 → What do the symbols ∆v

Answer 29

v

Question 30

A → ∆v represents the change in velocity

Answer 30

measured in metres per second (m/s).

Question 31

v represents the final velocity

Answer 31

measured in metres per second (m/s).

Question 32

u represents the initial velocity

Answer 32

measured in metres per second (m/s).

Question 33

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Question 34

**Q10 → What is average acceleration?**

Question 35

A → Average acceleration is the total change in velocity divided by the time taken for that change to occur. It tells us how much the velocity changes per second over a given time period.

Question 36

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Question 37

**Q11 → What is the formula for average acceleration?**

Question 38

A → Acceleration (m/s²) = Change in Velocity (m/s) ÷ Time (s)

Question 39

In shorthand form:

Question 40

a = Δv / t

Question 41

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Question 42

**Q12 → What do the symbols in the average acceleration equation represent?**

Question 43

A → In the equation a = Δv / t:

Question 44

* a (or α) is the acceleration

Answer 44

measured in metres per second squared (m/s²).

Question 45

* Δv is the change in velocity

Answer 45

measured in metres per second (m/s).

Question 46

* t is the time taken for the change

Answer 46

measured in seconds (s).

Question 47

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Question 48

**Q13 → What does uniform acceleration mean?**

Question 49

A → Uniform acceleration means constant acceleration. This means the acceleration does not change over time and the velocity changes by equal amounts in equal time intervals.

Question 50

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Question 51

**Q14 → What is another name for constant acceleration?**

Question 52

A → Constant acceleration is sometimes called uniform acceleration.

Question 53

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Question 54

**Q15 → What equation links final velocity

Answer 54

initial velocity

Question 55

A → For objects in uniform acceleration

Answer 55

the equation is:

Question 56

(final velocity)² − (initial velocity)² = 2 × acceleration × distance

Question 57

In shorthand form:

Question 58

v² − u² = 2as

Question 59

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Question 60

**Q16 → What do the symbols in the equation v² − u² = 2as represent?**

Question 61

A → In the equation v² − u² = 2as:

Question 62

* v is the final velocity

Answer 62

measured in metres per second (m/s).

Question 63

* u is the initial velocity

Answer 63

measured in metres per second (m/s).

Question 64

* a is the acceleration

Answer 64

measured in metres per second squared (m/s²).

Question 65

* s is the distance travelled or displacement

Answer 65

measured in metres (m).

Question 66

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Question 67

**Q17 → What does displacement (s) mean in the equation v² − u² = 2as?**

Question 68

A → Displacement is the distance travelled in a specific direction. It is measured in metres (m). In this equation

Answer 68

s represents displacement

Question 69

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Question 70

**Q18 → How can the uniform acceleration equation be rearranged to calculate final velocity?**

Question 71

A → Starting from:

Question 72

v² − u² = 2as

Question 73

Rearrange to:

Question 74

v² = u² + 2as

Question 75

Then take the square root to find v:

Question 76

v = √(u² + 2as)

Question 77

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Question 78

**Q19 → How can the uniform acceleration equation be rearranged to calculate acceleration?**

Question 79

A → Starting from:

Question 80

v² − u² = 2as

Question 81

Rearrange to make a the subject:

Question 82

a = (v² − u²) / 2s

Question 83

This can be used if the initial velocity

Answer 83

final velocity

Question 84

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Question 85

**Q20 → How can the uniform acceleration equation be rearranged to calculate initial velocity?**

Question 86

A → Starting from:

Question 87

v² − u² = 2as

Question 88

Rearrange to:

Question 89

u² = v² − 2as

Question 90

Then take the square root to find u if required.

Question 91

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Question 92

**Q21 → How can the uniform acceleration equation be rearranged to calculate displacement?**

Question 93

A → Starting from:

Question 94

v² − u² = 2as

Question 95

Rearrange to make s the subject:

Question 96

s = (v² − u²) / 2a

Question 97

This can be used if the initial velocity

Answer 97

final velocity

Question 98

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Question 99

**Q22 → What is acceleration due to gravity?**

Question 100

A → Acceleration due to gravity (g) is the uniform acceleration experienced by objects in free fall near the Earth’s surface. It has a value of approximately 9.8 m/s².

Question 101

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Question 102

**Q23 → Why is acceleration due to gravity described as uniform?**

Question 103

A → Acceleration due to gravity is described as uniform because it is constant for objects in free fall near the Earth’s surface. This means the acceleration does not change as the object falls.

Question 104

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Question 105

**Q24 → How is acceleration due to gravity related to gravitational field strength?**

Question 106

A → Near the Earth’s surface

Answer 106

the value of acceleration due to gravity (g)