Ch. 9 microbial genetics Flashcards

(32 cards)

1
Q

LAC operon

A

Present: binds to a repressor molecule, allowing translation to occur
Absent: the repressor molecule will inhibit RNA polymerase from transcribing RNA.
- Genes are involved in turning lactose into proteins.

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2
Q

3 Forms of bacterial genetic exchange

A
  • conjugation
  • transduction
  • transformation
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3
Q

Direct Contact conjugation

A
  1. conjugation pilus of the donor links to recipient
  2. F factor (Plasmid info) is copied and transferred to the recipient
  3. A partial chromosome is copied and relayed into the recipient cell, where it is integrated into the bacterial cell.
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4
Q

Transformation of exogenous DNA

A
  1. External DNA fragment will bind to protein receptor on outside of cell.
  2. DNA fragment will become single stranded and simple to enter the cell
  3. DNA will align with corresponding DNA sequence within the cell
  4. DNA will incorporate into the bacterial DNA.
  5. At this point external DNA is now incorporated fully into the original bacterial DNA.
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5
Q

Transduction via virus vectors

A
  1. Virus will inject DNA into host cell
  2. Viral proteins replicate within cell
  3. Some bacterial chromosomal information becomes incorporated into virus
  4. once lysed, virus transduces the original host bacterial information into another host.
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6
Q

Plasmid

A

small circular form of DNA
typically in prokaryotic organisms, playing a role in survival

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7
Q

which direction does DNA polymerase read from?

A

from 5’ to 3’ direction

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8
Q

Helicase

A

breaks hydrogen bonds within DNA strand

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9
Q

topoisomerase

A

prevents dna from coiling once separated

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10
Q

SS binding protein

A

prevents dna from binding again

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11
Q

DNA pol 1

A

replaces primers with DNA

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12
Q

Ligase

A

mends okazaki segments

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13
Q

Describe bidirectional bacterial replication

A
  1. Ori represents region that replication begins
  2. two replication forks move away from one another in opposite directions
  3. replication forks continue circular until meet at termination sequence
  4. Each new strand contains original strand. (semiconservative)
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14
Q

Rolling replication

A

present in plasmid replication,
- polymerase begins on the plasmid
- replicates and moves with SS binding protein replicating.
- one strand is replicated

https://www.youtube.com/watch?v=jmWuju1S9_E

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15
Q

Central Dogma of biology

A

the fundamental flow of DNA to RNA to Protein.

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16
Q

Can mRNA be read directly after synthesis?

A

No, it must undergo intron removal and exon binding within the nucleolus.

17
Q

Difference between DNA and RNA

A
  • two prime -OH group
  • single-stranded
  • utilizes Uracil, not thymine
18
Q

Transcription

A

-RNA polymerase makes a copy of template strand from 5’ to 3’.
- tRNA will bring copied strand to ribosome to make protein.

19
Q

RNA processing

A
  • Primary mRNA transcript contains Introns that are excised and Exons that are kept and bound together following intron removal
  • This occurs in the nucleus and allows mRNA to be translated in the cytoplasm
20
Q

tRNA

A

carriers of amino acids to form peptide bonds in the ribosome

21
Q

stop codons

22
Q

Riboswitch

A
  • regulates translation at the ribosome
  • binds to mRNA
  • Ligand binding to mRNA can inhibit ribosome protein synthesis.
23
Q

What does Lac I code for?

A

codes for lac operon that inhibits the repressor protein

24
Q

Define Horizontal gene transfer

A

genetic material is shared between two organisms that are not parents and offspring.

25
Transformation with DNA fragments or plasmid
DNA fragments can be integrated or degraded to be incorporated OR A plasmid can be taken into a cell completely, allowing it to remain in the cell unintegrated, but it will affect the cell.
26
Base substitution
replaces one amino acid in codon
27
missense mutation
changes codon and results in non functioning protein
28
silent mutation
single nucleotide change that doesn't result in misfunctioning protein
29
nonsense mutation
results in an early stop codon being produced
30
frameshift mutation
shifts amino acids to shift downstream - resulting in a misfunctioning protein, short protein, or early stop codon.
31
AMES test
tests if a chemical can cause mutation
32
AMES test with bacteria
testing on his(-) bacteria. Control contains no histidine, the pother does and is treated with chemical. - presence of colonies shows that mutations occured.