moles
mass (g)/ molar mass
mass (g)
moles x molar mass
particles
moles x 6.022 x10^23
gas volume
moles x 22.4L
percent yield
actual/theoretical x 100
percent composition
mass of element/ total molar mass x 100
Percent water
mass of water lost/mass of hydrate x 100
stoichiometry step 1:
balance equation
stoichiometry step 2:
convert give value to moles
stoichiometry step 3:
use mole ratio: moles wanted/moles given
stoichiometry step 4:
convert moles to what is wanted
substance that runs out first and limits how much product forms.
limiting reactant
Theoretical yield
calculated maximum possible product
Actual yeild
Product actually obtained in lab