Deriving v = u + at
Gradient of velocity-time graph (a) = (v-u)/t
v = u + at
Deriving s = 1/2(v+u)t
Area under a velocity-time graph (trapezium)
Deriving v^2 = u^2 + 2as
Rearrange for t = (v-u)/a
Substitute into s = 1/2(v+u)t
Deriving s = ut + 1/2at^2
Substitute v = u + at into s = 1/2(v+u)t
Deriving s = vt - 1/2at^2
Substitute u = v - at into s = 1/2(v+u)t
Acceleration due to gravity
9.8 ms-2, give all answers to 2s.f.