Equation of a circle formula
(x-a)^2 + (y-b)^2 = r^2
what is the equation of the circle with centre (0,3) and radius 2
x^2 + (y-3)^2 = 2^2
does the circle with the equation
(x-8)^2 + (y-15)^2 = 17^2
pass through the origin
yes
(0-8)^2 + (0-15)^2 = 289
64 + 225 = 289
289 = 289
is the number is less than 289 then it is within the circle and if it is greater than 289 then it is outside the circle
equation to find the length of a line between two coordinates
length^2 = (y1 -y2)^2 + (x1-x2)^2
the perpendicular bisector of any chord will
pass through the centre of a circle
find the radius of the circle