Define Enthalpy change
Heat energy change at constant pressure
Describe the enthalpy change in an exothermic reaction (2)
What is the energy change in exothermic reactions and give examples of exothermic reactions (3 + 1)
What happens if there is an enthalpy change (2)
*Energy is transferred between the system and the surroundings
*The system is the chemicals and the surroundings is everything outside the chemicals
Describe the enthalpy change in an endothermic reaction (2)
*Energy is transferred from the surroundings to the system (absorb energy)
* Requires an input of heat energy
What is an example of an endothermic reaction (3) and what is the energy change in endothermic reactions
What is the standard enthalpy change of formation
What is the standard enthalpy of combustion
What are the 4 standard conditions
What does incomplete combustion lead to
Soot( carbon)
Carbon monoxide
Water
It will be less exothermic than complete combustion
What is the equation for energy change
Energy change (J)=Mass of solution (g) x Heat capacity (Jg^-1 K^1) x Temperature change (K)
Q= Mx Cp x Delta T
What are the errors in the calorimetric method?
Explain why bond breaking is endothermic and why bond forming is negative
What is calorimetry used for
To find how much heat is given out by a reaction by measuring a temperature change
How can you use a graph to find an accurate temp change
record the temp at regular intervals beginning a couple mins before the you start the reaction
Plot a graph of the results draw two lines of best fit one through the points when u started and then another after you started
Extend both lines so they both pass the time when the reaction started
The distnace between the two lines at the time the reaction started is the accurate temp change for the reaction
What does Hess’s Law state
The total enthalpy change of a reaction is independent of the route taken
Formula for Enthalpy chnage for combustion
ΔH = q/n,
where ΔHf is the enthalpy of formation, q is the heat energy, and n is the number of moles.
You get q (heat energy) from q=mcDelta T
Calculating the enthalpy change of reaction, (Delta)H from experimental data
General method
1. Using q = m x cp x T calculate energy change for quantities used
2. Work out the moles of the reactants used
3. Divide q by the number of moles of the reactant not in excess to give H
4. Add a sign and unit (divide by a thousand to convert Jmol-1
to kJmol-1
you neeed to know this
Also assume that the solutions have the density of water, which is 1g cm-3 . Eg 25 cm3 will weigh 25g
Signs for reactions
If there is a temp change that is posiitve th answer ,ust be given as a negative and vice versa wih a negative temp change
Calculate the enthalpy change of reaction for the reaction where 25.0cm3 of 0.200 mol dm-3
copper sulfate was reacted with 0.0100mol (excess of zinc). The temperature increased 7.0 oC .
Step 1: Calculate the energy change for the amount of reactants in the calorimeter.
Q = m x cp x T
Q = 25 x 4.18 x 7
Q = 731.5 J
Step 2 : calculate the number of moles of the reactant not in excess.
moles of CuSO4 = conc x vol = 0.20 x 25/1000
= 0.005 mol
Step 3 : calculate the enthalpy change per mole which is often called the enthalpy change of reaction
H = Q/ no of moles
= 731.5/0.005
= 146300 J mol-1 = 146 kJ mol-1
to 3 sf
Finally add in the sign to represent the energy change: if temp increases
the reaction is exothermic and is given a minus sign e.g. –146 kJ mol-1
Example 2. 25.0cm3 of 2.00 mol dm-3 HCl was neutralised by 25.0cm3 of 2.00 mol dm-3 NaOH. The temperature increased 13.5oC
Calculate the enthalpy change per mole of HCl.
Step 1: Calculate the energy change for the amount of reactants in the calorimeter.
Q = m x cp x T
Q = 50 x 4.18 x13.5
Q = 2821.5 J
Step 2 : calculate the number of moles of the HCl. moles of HCl = conc x vol
= 2 x 25/1000
= 0. 05 mol
Step 3 : calculate H the enthalpy change per mole which might be called the enthalpy change of neutralisation
H = Q/ no of moles
= 2821.5/0.05 = 56430 J mol-1 = -56.4 kJ mol-1
to 3 sf Exothermic and so is given a minus sign
Example 3. Calculate the enthalpy change of combustion for the reaction where 0.650g of propan-1-ol
was completely combusted and used to heat up 150g of water from 20.1 to 45.5oC
Step 1: Calculate the energy change used to heat up the water.
Q = m x cp x T
Q = 150 x 4.18 x 25.4
Q = 15925.8 J
Step 2 : calculate the number of moles of alcohol combusted.
moles of propan-1-ol = mass/ Mr
= 0.650 / 60 = 0.01083 mol
Step 3 : calculate the enthalpy change per mole which is called cH (the enthalpy change of combustion)
H = Q/ no of moles
= 15925.8/0.01083
= 1470073 J mol-1 = 1470 kJ mol-1
to 3 sf
Finally add in the sign to represent the energy change: if temp increases
the reaction is exothermic and is given a minus sign eg –1470 kJ mol-1
Errors in this method