✅ Answer: C – 15%
Justification: CV = (6 / 40) × 100 = 15%; measures relative dispersion of data.
✅ Answer: A – Zero
Justification: Σ(x − x̄) = 0 for any set — a property of the arithmetic mean.
✅ Answer: B – Median
Justification: Median depends only on middle position, not on magnitude of extreme values.
✅ Answer: A – Zero
Justification: Perfect symmetry → no skewness.
✅ Answer: B – 68%
Justification: Empirical Rule: ±1σ = 68%, ±2σ = 95%, ±3σ = 99.7%.
✅ Answer: B – Variance
Justification: σ² = variance, basic formula of dispersion.
✅ Answer: C – 1.5
Justification: z = (x − μ)/σ = (85 − 70)/10 = 1.5.
✅ Answer: C – Positive
Justification: Direct relationship → r > 0.
✅ Answer: B – −1 to +1
Justification: r measures strength and direction of linear relation.
✅ Answer: C – 7
Justification: Most frequent value is 7.
✅ Answer: C – Discrete/Continuous
Justification: Histogram visualizes frequency distribution of numerical data.
✅ Answer: C – Quartile Deviation
Justification: (Q3 − Q1)/2 covers central 50% spread.
✅ Answer: B – 28
Justification: Mode ≈ 3Median − 2Mean → 25 = 3M − 60 → M = 28.33.
✅ Answer: B – 0.5
Justification: One favorable event out of two possible.
✅ Answer: B – Independent
Justification: No linear relationship exists (uncorrelated).
✅ Answer: C – Normal
Justification: Symmetrical bell curve = normal distribution.
✅ Answer: C – 0.7
Justification: P(success) = 1 − P(failure) = 0.7.
✅ Answer: B – 6
Justification: Σx/n = 30/5 = 6.
✅ Answer: B – Ogive
Justification: Ogive plots cumulative frequencies vs. class boundaries.
✅ Answer: D – 40
Justification: Σx = n × mean = 5 × 8 = 40.
✅ Answer: B – Sum of Squares of Errors
Justification: Least Squares Method criterion.
✅ Answer: B – 1
Justification: Total probability = 1.
✅ Answer: A – Estimator
Justification: It estimates unknown population parameter.
✅ Answer: C – Unchanged
Justification: Shift affects mean but not spread.