Exam 2 Flashcards

(70 cards)

1
Q

Explain a substances tendency related to the change in gibbs energy for phase changes

A

A substance will have a tendency to change to a lower gibbs energy
- if phase #1 has a higher gibbs energy than phase #2 the substance will have a tendency to spontaneously change to phase #2

this is why water freezes as ice at T less than 0 C

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2
Q

Fundamental gibbs equation

A

dG = VdP -SdT
- shows how gibbs energy relates to temperature and pressue if one of the variables is held constant

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3
Q

Fundamental gibbs equation at constant P

A

dG = -SdT
- as entropy increases gibbs energy decreases as more free energy is associated with the entropy of the system and less is available to do work or drive a process

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4
Q

Fundamental gibbs equation at constant T

A

dG= VdP
- where gibbs energy increases with increasing pressure as the stored energy of the system increases and more energy is availible to do work or drive processes

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5
Q

True or false?

Molar entropy increases with phase (s–l–g)

A

True! this is essential for understanding the fundamental Gibbs equation at constant pressure

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6
Q

When two phases are in equilibrium their molar gibbs energies are —

A

equal

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7
Q

True or false?

The forward and reverse reactions are equal only for the liquid to vapor phase boundary.

A

False, at all phase boundaries, at any point along the line the foward and reverse rates are equal

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8
Q

Dynamic equilibrium

A

Two phases in equlibrium transitioning into the other are occuring at an equal rate

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9
Q

Vapor pressure

A

pressure of the vapor when in equilbrium with the liquid phase
- increases with increasing temperatue as more molecules leave the liquid phase and join the vapor phase

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10
Q

Clapeyron equation

A

dP/dT= delta trs. H/T* delta trs. V
- an exact expression for the slope of a tangent line to the phase boundary

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11
Q

Chemical potential=

A

molar gibbs energy

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12
Q

Chemical potentials of substances in equlibrium at a phase boundary must be —

A

equal

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13
Q

The slope of a phase boundary is—

A

dP/dT

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14
Q

Describe the solid liquid phase boundary

A

Usually very steep, positive, and linear

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15
Q

Clapeyron equation for the solid liquid phase boundary

A

pf = pi + delta trs. H/ delta trs. V * ln(T2/T1)
- ln(T2/T1)= T2-T1/T1 when T2 is close to the value of T1

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16
Q

Describe the vapor liquid phase boundary

A

not usually as steep as the solid liquid boundary, it is also not linear because there is a logarithmic relationship

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17
Q

Clausius- Clapeyron equation

A

d(lnP)=delta trs H* dT/RT^2
- lets us predict how the vapor pressure varies with temperature
- pf = pi *e^x
- x= - delta trs H/ R(1/Tf-1/Ti)

liquid vapor phase boundary

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18
Q

Supercritical fluid

A

forms when the pressure is increased at a temperature past the critical temperature and the vapor will not condense into a liquid despite increased pressure

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19
Q

boiling temperature

A

the temperature when vapor pressure of a liquid is equal to the external pressure

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20
Q

Solute

A

what is dissolved, in smaller quantities

‘B’

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21
Q

Solvent

A

what the solute is dissolved in, in larger quantities

‘A’

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22
Q

Chemical potential for an ideal gas

start with fundamental gibbs equation for derivation

A

uj = uj (o) + RTln(pj)

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23
Q

True or false?

Chemical potential of an ideal gas increases with increasing partial pressure in the mixture?

A

True! There is a logarithmic relationship

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24
Q

Raoults law

A

for ideal solutions when partial vapor pressure of a substance in a mixture is proportional to the mole fraction and its vapor pressure as a pure liquid
pj= xj x pj*

P=PA+ PB

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25
Henrys law
for ideal dilute solutions where the partial pressure of a volatile solute, B, in solvent, A, is proportional to henrys law constant and its mole fraction in solution PB = K'H x xB [J]= KHpj - note difference between KH and K'H
25
Activities (aj)
an effective concentration that accounts for deviations from actual concentrations in solution
26
Activity for an ideal solution
aj = xj
27
Activity for an ideal dilute solution
aj= xj x gammaj | gamma j = acitivty coefficent
28
how does the activity coefficent change for raoults law? | and/or ideal solutions?
gamma approaches one as the mole fraction approaches one | mole fraction of one = pure solvent
29
how does the acitivity coefficent change for henrys law? | and/or ideal- dilute solutions?
gamma approaches one as the molar concentration approaches zero | molar concentration of zero = pure solvent/ no solute
30
Equation for the change in gibbs energy for dissolving two components together (solvent and solute) | start with the molar gibbs energies of both in terms of chemical potent
delta G = nRT(xA * ln(xA) + xB * ln(xB))
31
Equation that tells us that the entropy is maximized during formation of solution - start with fundamental gibbs equation and substitute in equation that represents delta G in terms of chemical potentials
Delta S = -nR(xA * ln(xA) + xB * ln(xB))
32
The driving force for spontaneous mixing is ---- the --- of the system
1. maximizing 2. entropy
33
Colligative properties
properties that only depend on the number of particles (**not the type**) present in the solution | ex: bp elevation, fp depression, osmotic pressure
34
What are the two assumptions we make to explain freezing point depression and boiling point elevation? | graph from slides with pure liquid, soln, solid and vapor
1. The solute does not dissolve in the solid form of the solvent 2. The solute is not volatile and does not contribute to the vapor pressure | essentially, it is only present in solution
35
Explain what is happening at a molecular level during freezing point depression
The addition of a solute to a solvent reduces the freezing point because entropy is maximized during the process and the increase in randomness requires a decrease in the freezing point temperature to overcome the entropy
36
Explain what is happening at the molecular level during boiling point elevation
The addition of a solute to a solvent decreases the vapor pressure which means in order to reach the temperature where vapor pressure and external pressure are equal (for boiling) a higher temperature is required to increase the number of molecules in the vapor state and therefore increase vapor pressure
37
Formula to calculate change in boiling point for boiling point elevation - start with chemical potential of a pure gas = chemical potential of a liquid + RTln(xA)
delta Tb = KxB K =RT^2/ delta vap H
38
formula to calcualte change of freezing point for freezing point depression
delta Tf = K'xB K' = RT^2/ delta fus H
39
Osmosis
the movement of a solvent across a semi permeable membrane from high concentrations of solvent to low concentrations of solvent - membrane is only permeable to solvent - The driving force is to get equal concentrations of solute on either side
40
Osmotic pressure
the pressure required to stop movement of solvent across the semi permeable membrane
41
In an osmotic set up --- and --- are equal at equilibrium | essential for deriving vant Hoff equation
1. uA* (p) 2. uA (p + pi)
42
Vant Hoff equation for osmotic pressure - start with the fact that the chemical potentials are equal on either side of the membrane
pi = RT [B] [B] = nB/V (molar concentration of solute)
43
At constant temperature and constant pressure --->--- for a non spontaneous change
1. delta G 2. 0
44
Describe the direction a reaction procedes in concerning gibbs energy for an equilibrium reaction
A reaction will proceed towards minimizing G at equilibrium (remember graph with three different plots showing spon, non-spon and at equilibrium)
45
Formula for calculating reaction gibbs energy ( delta r G) - start with chemical potential of a substance using activity (aJ) and delta r G in terms of chemical potentials and stoichiometric coefficents
delta r G = delta r G standard + RTln(Q)
46
What are the conditions for biological standard state?
pH = 7 so [H3O+] = 1.0 *10^-7
47
# True or false? For H3O+ the biological standard state gibbs is not equal to the thermodynamic standard state gibbs?
True, for species that are not H+ they are equal
48
How does the reaction proceed if K > 1?
the reaction proceeds to products and the change in standard gibbs energy is negative
49
How does the reaction proceed if K < 1?
The reaction proceeds to reactants and the change in standard gibbs energy is positive
50
What relationship does T have to have with the standard enthalpy over the standard entropy for the reaction to depend on enthalpy?
T must be less than the term of standard enthalpy over standard entropy
51
What relationship does T have to have with standard enthalpy over standard entropy for the entropy term to dominate?
T must be greater than the term of standard enthalpy over standard entropy
52
# True or false? At equilibrium the standard reaction Gibbs energy is equal to zero which yields the equation change in reaction Gibbs energy = - RTln(K)
False, at equilibrium it is the change in reaction Gibbs energy that is equal to zero
53
Explain the stability of a reaction when delta f G is positive
If the change in Gibbs energy of formation is positive this means that reactants are favored and unstable products will decompose
54
Explain the stability of a reaction when delta f G is negative
If the change in Gibbs energy of formation is negative the products are favored and stable and will not decompose
55
vant Hoff equation - start with the equation of change in reaction Gibbs energy at equilibrium | shows the relationship between two different equilibrium constants
ln(K2)= ln(K1) + delta r H/ R (1/T1- 1/T2)
56
Transfer potential
the energy available to drive a non spontaneous process that comes from the release of a spontaneous process - a spontaneous reaction can drive a non-spontaneous reaction forward
57
Brosted Lowy Theory of acids and bases
Acids: are proton donors Bases: are proton acceptors
58
Ka and Kb determine the --- of acids and bases
Strength
59
Strong acids/ bases make --- bases/ acids
weak
60
Weak acids
acids that are not completely deprotonated in solution
61
Weak bases
bases that are not completely protonated in solution
62
Kw =
[H3O+][OH-] - at 25 C Kw = 1.0 * 10^-14 and pKw = 14.00
63
When can you subsitute # for #-x in an I.C.E table?
When the concentration (x) is sufficently smaller than the inital concentration
64
Polyprotic acid
An acid with multipe protons to donate
65
Ka1 is always --- than Ka2 because --- is the most acidic proton
1. greater 2. Ka1
66
What does it mean for a molecule to be amphiprotic?
To be able to be a base and an acid at the same time | ex: an amino acid that has been deprotonated still with a proton
67
Qualifications to use the pH of an amphiprotic molecule equation
Ka1>> Ka2 S >>Kw/Ka2 S>> Ka1
68
pH of an amphiprotic molecule equation
pH = 1/2(pKa1 + pKa2)
69
Henderson Hasselbalch equation
pH = pka - log (acid/ base) | use for buffers