Factor by Grouping

Question 1

Use grouping to factor the polynomial 2y^3 + y^2 + 8y^2 + 4y.

Answer 1

• We pull out the common factor y2 from the first two terms and the common factor 4y from the second two terms to get: y2(2y + 1) + 4y(2y + 1).
• Then we factor out (2y + 1) from each term and obtain: (y2 + 4y)(2y + 1).