Kb/Ka=
10^-pk
pH=
-log([H+]/[OH-])
What does strong base indicate?
The base will FULLY dissociate
-> [base]=[OH-]
pH to find the concentration?
10^-xpH
What happen when the concentration of base is very Low?
•the contribution of base conc due to auto-ionisation of water is no longer negligible
•[OH-] acid = [OH-] NaOH + [OH-] H2O
= x
=> pOH= -log(x)