1
Q
Empirical formula
A
Lowest whole number ration of elements in a compound
2
Q
ef- C3H6 ->
A
CH2
3
Q
calculating EF - compound x contains 50% S and 50% O. What is EF of X (we have 100g of x)
A
50g - S : moles of S - 50/32=1.56m
50g - O :moles of O -50/16= 3.12m
3.12:1.56
2:1
EF= S2O (we need two O to have equal)
4
Q
use a table
A
mass
ram
moles
ratio
5
Q
mf of CH
- given the rfm of the compound is 78
- given the rfm of CH is 13
A
78/13 = 6
6x the ration
C6H6
6
Q
compound x contains 44.4% C, 3.7% H, 51.9% N - calculate EF
rfm
c-12
h-1
n-14
A
- 4/12=3.7
- 7/1=3.7
- 9/14=3.7
CHN
