to find pH?
-log(H+)
to find pOH when pH is given you?
subtract given fro 14 bc pH + pOH =14
to find pOH?
-log(OH-)
to find [H+}?
10^negative pH
to find [OH-]
10^ negative pOH
[H+][OH-]=
1 x 10^-14
molarity units
Mol/liters
calculating volume
M1V1=M2V2
** converting mL to L
multiply mL x 1000
grams per liter
M= grams solute/liters solution
molarity a.k.a moles per liter
M=moles of solute/liters solution
percent composition a.k.a mass percent
% mass = mass of solute / mass solution x 100
moles to grams
mol / 1 x molar mass/1 mol
grams to moles
grams/1 x 1 mol/molar mass