Calculus II > Half Angle Formula > Flashcards
Using half angles:
1/2 (1-cos(2θ)) = ?
= sin2θ
cos2θ = ?
= 1/2 (1+cos(2θ))
1/2 (1+cos(2θ)) = ?
= cos2θ
sin2θ = ?
= 1/2 (1-cos(2θ))
tan2θ = ?
= tan2θ