Linear relations week 3

Question 1

Special lines only contain one variable:

Answer 1

x = any number (vertical line)
slope unidentified
y = any number (horizontal line)
slope 0

Question 2

How do we find the equation of a line y = mx + b when given two points?

Answer 2

first, find the slope (m)

then, substitute one of the points x and y values into the y=mx+b along with the slope

Question 3

How do we find the equation of a line y = mx + b when given the slope and one point?

Answer 3

substitute x, y, and m into y=mx+b, then find the value of b (y-intercept)
Then, write the equation substituting m and b values into y=mx+b

Question 4

How do we find the equation of a line y = mx + b when given the slope and y-intercept?

Answer 4

substitute the m with the slope value and b with the y-intercept

Question 5

How do we graph a line equation?

Answer 5

start with the y-intercept and then move the rise and the the run.

Question 6

Slope formula:

m formula:

Answer 6

Slope: rise/run

m = y2 - y1 / x2 - x1

Question 7

y-intercept is represented by what variable?

Answer 7

b

Question 8

Direct variation characteristics:

Answer 8

• directly relies on independent value to get a result
• graph starts at origin (0,0)
• equation; y = mx
• variable cost: “per..” “each..”

Question 9

Partial variation characteristics:

Answer 9

• has an initial value
• relies on an independent value
• graph starts at y-axis (0,b)
• equation; y=mx+b
• fixed cost + variable cost

Question 10

List how to find the Point of Intersection (POI)

Answer 10

1. write equation for each line y=mx+b
2. create a table of values for each
3. graph each line
4. identify point of intersection
5. conditions defined

Question 11

Define point of intersection (POI):

Answer 11

A point where linear systems intersect

the ordered pair where 2 lines cross each-other