log(ab)
log(a) + log(b)
log(a/b)
log(a) - log(b)
log(a^n)
n * log(a)
log(base “a”) (a)
1
log(base “a”) (1)
0
natural log = ln(x)
log(base “e”) (x)
log(base10) (x) is written as…
log(x)
log(10)
1
log(1)
0
write 2^x = 16 in log form
log (base 2) (16) = x
log(base2)(16) = x in words
What power do I need to raise 2 to in order to get 16? I’ll set that power as equal to x.
write log(base3) (81) in exponent form
3^x = 81