If y = a↑x, then x =
x= log🠗a(y)
log🠗a(x/y)
= log🠗a(x) - log🠗a(y)
log🠗a(xy)
= log🠗a(x) + log🠗a(y)
log🠗a(x↑n)
= n log🠗a(x)
If y = ln(x), then what does dy/dx equal
dy/dx = 1/x
If y = ln f(x), then what does dy/dx equal
dy/dx = f’(x)/f(x)
If y = log🠗a(x), then what does dy/dx equal
dy/dx = 1/xln(a)
log🠗a(b)
1 / log🠗b(a)