laws of indices
i cant type this put js memorise it or sum lol reminder to self
forms for quadratic equations (hint;GEmsFAvouriteVerses)
generalised: y= ax^2 + bx + c, a not equal 0
factorised; a(x-p)(x-q), a not equal 0
vertex form; a(x-h)^2 +k, a not equal 0
how to find intercepts
when y=0, x+
when x=0, y=
(1-x)^2 is equal to (x-1)^1? T or F
T. (1-x)^2= [-(x-1)]^2 = ( x-1)^2
what am i writing EXPAND IT
complete square????
x^2 + bx = (x+b/2)^2 - ( b/2)2 ( + constant k)
factorise the first two values first then use distributive law )#&$)#&!)(&$
quadratic formula..
axe equals neg bee plus minus sqare root bee sqare minus four aye see over two aye