What is alpha radiation?
-fast moving particles, helium nuclei
- 4
Helium
2
What is beta radiation?
Electrons with speeds just less than speed of light ejected from radioactive nuclei
- 0
B
-1
What is gamma radiation?
A
Z
x
-a is the mass number (number of protons and neutrons)
- x is the atomic number (number of protons)
What is half life?
-the time taken for the number of radioactive nuclei, to reduce to one half of it’s initial value
- unit - s
What is activity?
-the rate of decay of a sample of radioactive nuclei
-unit - Bq or s^-1
Alpha radiation properties?
-positive charge, +2e.
-strongly ionising.
-low penetrating power
-stopped by skin or paper.
-deflected by electric and magnetic fields.
Beta radiation properties?
-negative charge, -e.
- weakly ionising.
-greater penetrating power than α-particles.
-stopped by a few millimetres of aluminium.
- deflected easily by electric and magnetic fields.
Gamma radiation properties?
-electromagnetic radiation of very high frequency.
- no charge.
-very weakly ionising.
-very high penetrating power.
- intensity is reduced by thick lead.
-not deflected by electric and magnetic fields.
How do alpha move in magnetic and electric fields?
How do beta move in magnetic and electric fields?
How do you make allowances for background radiation in experimentsl measurements?
-subtract background count from count from material
Activity equation?
Initial activity/ 2^half life
What is one Becquerel equal to?
Why is the actvity equation the way it is?
-The negative sign is needed here as N decreases with time and A is the rate of decay
-This equation shows that the activity, A, is directly proportional to the number of radioactive nuclei, N, present in the sample.
-As time passes and a radioactive substance decays, then both N and A will decrease.
-After one half-life, the values of N and A will both halve
How to derive time constant equation?
The activity, A, of a sample of radioactive material decreases exponentially with time, t.
So: A=Aoe^−λt
The half-life, T ½, is the time taken for the activity to fall to half of its initial value.
Therefore: when t=T½, A/ Ao =½
We can re-write the equation above as:
A/Ao =e^−λt
Substituting gives
1/2 =e^−λT 1/2
If we find the reciprocal of each side, then the minus sign disappears and we have:
2=e^λT 1/2
Taking natural logs (ln) of both sides gives:
ln 2=λT 1/2
Therefore:
λ=ln2/T 1/2
Investigation of radioactive decay using dice practical?
What is radioactive decay based on?
Decay constant units?