find gdashedx
e^3xsec2x(3+2tan2x)
derivative of sec2x
2sec2xtan2x
x-coordinate of stationary point C
-0.49
x cannot be
e^2
explanation for > 0
A co-ordinate
(-4,0)
At B, t=
-2
At intersection, t =
20/7
At intersection, x =
-40/49
A =
1
B =
6
C =
-15
integral of x + 6 + (-15)/(x+2)
1/2x^2 + 6x - 15ln(x+2) + 15ln(2)
final answer for ln(2) integral
54 - 30ln(2)
integral of lnx/x^2
(-lnx -1)/x + c
Area under the curve
1 + 2ln2
final substitution
- 16