log a(a)=
1
log a(1)=
0
a^log a (b)=
b
log a (b)^n=
nlog a (b)
log a (m*n)=
log a(m) + log a(n)
log a (m/n)=
log a(m) - log a(n)
log a (1/b)=
-log a (b)
log a^n (b)=
1/n log a (b)
log a^n (b)^m=
m/n log a (b)
log a (b)= (Base Changing The.)
log c (b)/log c (a)
log a (b)(Base interchange)
1/log b (a)
a^log b (c)=
c^log b (a)