Squareroot of 12
2SR3 2 is before and 3 is under squareroot.
1st: 34, then break up 4, so 32*2, you have a pair, so put it before SR, 3 is as prime as it gets, so but it under the SR.
SR of x**5
SRxxxxx
two pairs of x´s and one left under sr so: x*x SRx
x**2SRx
SR45+SR20
45= SR 3*3*5 20= SR 2*2*5
then it is
3SR5 + 2SR5= 5SR5
SR5*SR6=
SR30
3SR5 * 2SR10
6SR50
6SR552
5*6SR2
30SR2