S3 Transition elements Flashcards

(49 cards)

1
Q

Transition element definition

A

A d-block element that can form at least one ion with an incomplete d sub-shell.

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2
Q

Why aren’t scandium and zinc transition elements

A

-Scandium only forms one stable ion Sc3+ which has an empty d sub-shell.

-Zinc only forms Zn2+ ions which have a full d sub-shell.

So neither form ions with incomplete d sub-shell.

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3
Q

Properties of transition elements

A

-Can form coloured compounds.

-Have more than one oxidation state for each element in its compounds.

-Transition elements and their compounds can be used as catalysts due to variable oxidation states meaning they can facilitate electron transfer between reactants.

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4
Q

Benefits of catalysts and risk

A

-Increase rate of reaction at lower temps and pressures, reducing energy usage and cost which benefits industry and the environment.

-Potential health risks as many are toxic.

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5
Q

Examples of transition elements as catalysts

A

-MnO2 catalyses decomposition of hydrogen peroxide.

-Cu+ ions catalyse reaction of zinc with acids.

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6
Q

Complex ion definition

A

Metal ion surrounded by co-ordinately bonded ligands.

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7
Q

Ligand definition

A

An atom, ion or molecule which can donate a lone electron pair to a central metal ion to form a coordinate/dative covalent bond.

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8
Q

Examples of monodentate ligands

A

H2O
Cl–
NH3

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9
Q

Bidentate ligand example

A

NH2CH2CH2NH2 (1,2-diaminoethane also known as ‘en’)

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10
Q

Coordination number

A

The number of coordinate bonds attached to central ion

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11
Q

Octahedral complex ion examples

A

Many hexaaqua complexes:
-[Cu(H2O)6] 2+
-[Fe(H2O)6] 3+

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12
Q

Tetrahedral complex ion examples

A

Many tetrachloro complexes:
-CuCl4 2–
-CoCl4 2–

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13
Q

Square planar complex ion examples

A

Complexes of Pt, e.g. platin:
-Pt(NH3)2Cl2

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14
Q

Things that should be included when drawing complex ions

A

-Arrow heads to show dative covalent bonds.

-Lone pairs

-Arrows coming from specific atom of ligand that has lone pair.

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15
Q

How to identify cis or trans isomerism in octahedral and planar complexes

A

-Cis isomers have identical ligands next to each other with a bond angle of 90 degrees between them.

-Trans isomers have identical ligands opposite each other with a bond angle of 180 degrees between them.

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16
Q

Describe the structure of cis-platin

A

Square planar complex with two Cl- ligands and two NH3 ligands coordinately bonded to platinum (ll) with the same ligands next to each other.

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17
Q

When does optical isomerism occur?

A

Occurs in octahedral complexes containing 2 or more bidentate ligands.
(A type of stereoisomerism)

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18
Q

How is cis-platin used as an anti-cancer drug?

A

Used in chemotherapy by displacing chloride ligands and forming coordinate bonds with nitrogen atoms on DNA molecules in the cancerous cell, preventing the cancer cell from replicating.

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19
Q

Transition element ions in solution exist as ……

A

Hexaaqua complex ions (has six water ligands attached to it).

For example Cu2+(aq) is [Cu(H2O)6]2+(aq)

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20
Q

Cu2+ ions in water

A

Light blue solution of [Cu(H2O)6]2+(aq)

21
Q

Reaction of [Cu(H2O)6]2+(aq) with concentrated HCl (aq)

A

-Forms yellow solution of [CuCl4]2-
as water ligands displaced by chloride ligands.

-Tetrahedral complex with coordination number of 4 formed as chloride ligands bigger than water ligands.

22
Q

What happens if water is added to [CuCl4]2- (aq)

A

Water ligands displace chloride ligands as reversible reaction. Light blue solution of [Cu(H2O)6]2+(aq) is reformed but paler due to being more dilute from added water.

23
Q

Why might the solution turn green in the reaction between [Cu(H2O)6]2+(aq) and conc HCl (aq)

A

As yellow solution of [CuCl4]2- is formed from blue solution of [Cu(H2O)6]2+(aq), both coloured solutions can mix forming a green solution.

24
Q

Reaction between [Cu(H2O)6]2+(aq) and dropwise NH3(aq) or dropwise NaOH(aq)

A

-Light blue precipitate of Cu(OH)2(s) / Cu(OH)2(H2O)4 (s) is formed.

-This is due to NH3 and NaOH being bases so accepting H+ ions from H2O.

No square brackets for precipitates.

Cu(OH)2(s) = Cu(OH)2(H2O)4 (s)

25
Reaction between [Cu(H2O)6]2+(aq) and excess NH3(aq)
-Dark blue solution of [Cu(NH3)4(H2O)2]2+ (aq) formed. (Cu(OH)2 (s) intermediate redissolves in excess ammonia but is insoluble in excess OH- (aq).)
26
Cr3+ ions in water
Violet solution of [Cr(H2O)6]3+ (aq)
27
[Cr(H2O)6]3+ (aq) in dropwise NaOH or dropwise NH3
Grey-green precipitate of Cr(OH)3 (s)
28
[Cr(H2O)6]3+ (aq) in excess NaOH
Dark green solution of [Cr(OH)6]3- (aq)
29
[Cr(H2O)6]3+ (aq) in excess NH3
Purple solution of [Cr(NH3)6]3+ (aq)
30
Mn2+ ions in water | Include colour of solution
Pale pink solution of [Mn(H2O)6]2+ (aq)
31
Fe2+ ions in water
Light green solution of [Fe(H2O)6]2+ (aq)
32
Fe3+ ions in water
Pale yellow solution of [Fe(H2O)6]3+ (aq)
33
[Fe(H2O)6]3+ (aq) reaction with dropwise NaOH(aq) OR with dropwise NH3(aq)
Orange-brown precipitate of Fe(OH)3 (s)
34
[Fe(H2O)6]2+ (aq) reaction with dropwise NaOH(aq)
Green precipitate of Fe(OH)2 (s) If left standing in air, oxidises to orange brown precipitate of Fe(OH)3 (s)
35
[Fe(H2O)6]2+ (aq) reaction with dropwise NH3(aq)
Green precipitate of Fe(OH)2 (s)
36
[Mn(H2O)6]2+ (aq) reaction with dropwise NaOH(aq)
Light brown precipitate of Mn(OH)2 (s) If left standing in air, oxidises to dark brown Mn(OH)3 (S)
37
[Mn(H2O)6]2+ (aq) reaction with dropwise NH3 (aq)
Light brown precipitate of Mn(OH)2 (s)
38
How is O2 transported in the blood?
At the lungs, O2 ligand displaces H2O ligand in haem group of haemoglobin molecule (protein in red blood cells), forming reversible coordinate bond with Fe2+ ion, forming oxyhaemoglobin. This is then transported in blood to where needed in the body and H2O ligand displaces O2 ligand so O2 can be absorbed by respiring cells.
39
What happens when carbon monoxide (CO(g)) is inhaled ?
CO ligand can displace O2 and H2O ligands and bind more strongly and irreversibly to Fe2+ ions, forming carboxyhaemoglobin. This means O2 can no longer bind to and be carried by haem groups, leading to reduced oxygen being carried in blood stream to cells so reduced cellular respiration and potential death.
40
How can you test for transition metal ions?
Add dropwise aqueous sodium hydroxide NaOH(aq) and a coloured precipitate should form. (Same as previous)
41
How can Fe2+ and Fe3+ ions be interconverted
-Fe2+ oxidised to Fe3+ by manganate ions (MnO4-) being reduced to Mn2+. Purple solution -> Colourless solution -Fe3+ reduced to Fe2+ by I- ions. Orange-brown solution (or yellow???) -> Brown solution of I2 (aq) | Pale green Fe2+ ions obscured by formation of brown I2 (aq)
42
How is Cu2+ reduced to Cu+?
By an excess of I- ions Colour change: Light blue solution -> White precipitate of CuI(s) in Brown solution of I2 (aq) ## Footnote 2Cu2+ (aq) + 4I- (aq) → 2CuI (s) + I2 (aq)
43
What happens when Cu2O(s) reacts with hot dilute H2SO4(aq) ?
Cu+ ions undergo disproportionation forming Brown Cu (s) precipitate (oxidation state 0) in Blue solution of CuSO4 (oxidation state +2) ## Footnote Cu2O(s) + H2SO4(aq) -> Cu(s) + CuSO4 (aq) + H2O(l)
44
How is acidified Cr2O7 2- reduced to Cr3+ ?
By addition of zinc. Orange solution -> Green solution Cr2O72- (aq) + 14H+ (aq) + 3Zn (s) → 2Cr3+ (aq) + 7H2O (l) + 3Zn2+ (aq) Cr3+ reduced further to Cr2+ in excess zinc. Green solution -> Light blue solution Zn (s) + 2Cr3+ (aq) → Zn2+ (aq) + 2Cr2+ (aq)
45
How is Cr3+ oxidised to CrO4 2-
By addition of hot alkaline H2O2 (aq) Dark green solution -> Yellow solution 3H2O2 (aq) + 2Cr3+ (aq) + 10OH- (aq) → 2CrO42- (aq) + 8H2O (l)
46
How is CrO4 2- oxidised to Cr2O7 2-?
Addition of dilute sulfuric acid. Yellow solution -> Orange solution ## Footnote 2CrO42- (aq) + 2H+ (aq) → Cr2O72- (aq) + H2O (l)
47
3.528g of a group 2 metal, M, is reacted with an excess of chlorine. The reaction forms 9.775g of a chloride. What is metal M?
Calcium ## Footnote 1. Predict formula of chloride (MCl2) 2. Find mass of Cl2 3. Use this to find moles of Cl2 4. Use this to find moles of M 5. Use mass/moles to find mr of M.
48
Definition of a bidentate ligand
Species with two lone pairs of electrons which form two coordinate bonds by donating lone electron pairs to a central metal ion.
49
Can complex ions containing three of the same bidentate ligands, form optical isomers?
Yes