solve the simultaneous equations
2x+3y=53 A
3x-y = 19 B
1) multiply equation A by 3
- > Ax3 = 9x - 3y = 57
2) then add (in this case)
2x + 3y = 53
9x - 3y = 57
—————-
11x = 110
x = 10
3) substitute x value to find out y
-> 2(10) + 3y = 53
20 + 3y = 53
-20 -20
3y = 33
divide by 3
y=11
answer y=11
x=10
Two families go to the theatre
The pritchard family of 2 adults and 3 children pay £48
The luther family of three adults and five children pay 76
workout cost of one adult ticket and one child ticket
MAKE IT A SIMUILTANEOUS EQUATION AND THEN SOLVE :
2a + 3c = 48
3a + 5c = 76
AND .. SOLVE :)