Trigonometry Flashcards by Angelini THEINE

Q

cos² + sin² = ?

A

1

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Q

cos(-x) = ?

A

cos(x)

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Q

sin(-x) = ?

A

-sin(x)

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Q

cos(π + x) = ?

A

-cos(x)

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Q

sin(π + x) = ?

A

-sin(x)

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Q

cos(π/2 - x) = ?

A

sin(x)

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Q

sin(π/2 - x) = ?

A

cos(x)

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Q

cos(π/2 + x) = ?

A

-sin(x)

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Q

sin(π/2 + x) = ?

A

cos(x)

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Q

cos(0) = ?

A

1

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Q

sin(0) = ?

A

0

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Q

cos(π/6) = ?

A

√3/2

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Q

sin(π/6) = ?

A

1/2

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Q

cos(π/4) = ?

A

√2/2

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Q

sin(π/4) = ?

A

√2/2

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Q

cos(π/3) = ?

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A

1/2

Q

sin(π/3) = ?

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A

√3/2

Q

cos(π/2) = ?

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A

0

Q

sin(π/2) = ?

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A

1

Q

cos u = cos v implies ….

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A

u = v + 2kπ
OR
u = -v + 2kπ

Q

sin u = sin v implies ….

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A

u = v + 2kπ
OR
u = π-v + 2kπ

Q

cos(a+b) = ?

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A

cos(a)cos(b) - sin(a)sin(b)

Q

cos(a-b) = ?

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A

cos(a)cos(b) + sin(a)sin(b)

Q

sin(a+b) = ?

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A

sin(a)cos(b) + cos(a)sin(b)

sin(a-b) = ?

sin(a)*cos(b) - cos(a)*sin(b)

cos(2*a) = ? (3 forms)

1) cos²(a) - sin²(a) 2) 1 - 2*sin²(a) 3) 2*cos²(a) - 1

sin(2*a) = ?

2*sin(a)*cos(a)

cos²(a) = f(cos(2*a))

(1 + cos(2*a)) / 2

sin²(a) = f(sin(2*a))

(1 - cos(2*a)) / 2

cos(a)*cos(b) = ?

1/2*[cos(a+b) + cos(a-b)]

sin(a)*sin(b) = ?

1/2*[cos(a-b) - cos(a+b)]

sin(a)*cos(b) = ?

1/2*[sin(a+b) + sin(a-b)]