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Question 1

describe hybridisation in an e- poor aromatic

Answer 1

• e- poor and p for poor so u have 1e- in the p orbital
• u have 2e- in the sp2 orbital so u can use this as a nuc
• u cant conjugate the e- around

Question 2

describe hybrisisation in an e- rich aromatic

Answer 2

e- rich so 2e- in the p orbital so the lone pair can be conjugated

• 1 in the sp2 orbital

Question 3

e- rich can add electrophile where

Answer 3

add in C2 or C3,, any carbon is the same but we lows prefer C2 bc theres more resonance structures for it

it = the + charge

Question 4

e- poor can add an electrophile where

Answer 4

on C3,, bc the + will then be on the C and not the N,, and N is an EWG so we dont want it to be positive.

Question 5

indole,, where do we want the electrophile added

Answer 5

lowks C3 or C2,, we dont want to break aromaticity.

Question 6

N is pyridine is what directing

Answer 6

METAAAA

Question 7

an OMe in pyridine is what directing

Answer 7

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