EMR Spectrum
EMR is comprised of rapidly alternating magnetic and electric fields that are at 90 deg to each other, where both are perpendicular to the direction of wave propagation. EMR travels at the speed of light through a vacuum. The EM spectrum describes these waves in based on wavelength, with lower energy/longer wavelength EMR (e.g. radio waves) at one end of the spectrum and high energy/shorter wavelength EMR at the higher end of the spectrum (e.g. gamma rays)
EMR spectrum components
Low to high:
Particle wave duality
EMR can exhibit properties of both waves and particles in different situations.
For example:
Photons of light exhibit particle-like behaviour during the photoelectric effect.
When visible light is refracted or reflected, it exhibits wave-like behaviour.
Production of X-rays
X-rays are EMR produced when applied voltage across tungsten anode and cathode cause the thermionic emission of electrons from the cathode to strike the tungsten anode. The electrons interact with the atoms of the anode to produce predominantly heat, bremsstrahlung radiation and characteristic radiation.
Bremsstrahlung radiation occurs when the emitted electron passes near the nucleus of an atom in the anode to experience attractive coulombic forces. The electron slows down due to these forces, and emits a photon of equivalent energy to the amount of kinetic energy lost in keeping with the law of conservation of energy. The trajectory of the electron is deviated, which can go on to interact with further atoms/electrons.
Characteristic radiation occurs when the electron with sufficient energy strikes an inner shell electron of the anode material atom. When this occurs, the electron in the shell is ejected and a vacancy within the inner electron shell is produced. Electrons from outer shells fill in this gap, and release energy in the form of photons equivalent to the energy difference between the shells. Since the binding energies of each shell are fixed and unique to each element, characteristic radiation is unique to each element. The electron emitted from the cathode must have energy just above the binding energy of the electron shell.
X-ray tube spectrum
An x-ray tube produces a continuous spectrum of x-rays of different energies, with the majority of x-rays at lower energies and decrease in intensity of x-rays with higher energies. Within the spectrum there are ‘spikes’ in the x-ray intensities at the energies that coincide with the characteristic radiation produced by the x-ray tube.
The majority of electrons will interact with the nuclei of the anode atoms at a distance (since the nucleus is so small compared with the size of the atom) and hence the majority of bremsstrahlung radiation is of lower energies.
The voltage produced by an x-ray generator is not always constant, and thus there will be a fluctuation in x-ray energies.
The characteristic radiation produced by an x-ray tube with tungsten anode is 70keV.
kV - X-ray Tube parameter
mA - X-ray tube parameter
Filtration: X-ray tube parameter
Waveform: X-ray tube parameter
Anode material: X-ray tube parameter
X-ray tube: Components
Glass housing:
Cooling oil:
Between the glass and metal housings, used to cool the x-ray tube
Metal Housing:
Cathode:
Anode:
Window:
Filters and collimators can be used to alter the x-ray beam.
Line focus principle
Heel effect and effect on image quality
The heel effect describes the attenuation of x-ray beam on the anode side of the beam due to increased distance travelled through the anode.
This means that the x-ray beam produced on the anode size is less than that on that cathode side, resulting in varied irradiation of the subject that can lead to uneven exposure of images.
The heel effect can be used advantageously by placing the thicker part of the patient on the cathode side of the x-ray beam and the thinner part to the anode side. This will result in a more even exposure. E.g. in MMG, the thicker chest wall is positioned over the cathode side of the beam.
Factors that affect heel effect:
X-ray generators
X-ray generators produce the voltage required to apply across the x-ray tube to produce x-rays. The ideal voltage output from an x-ray generator is constant voltage with little ripple (difference between the peak and trough voltages).
Single phase, unrectified x-ray generators will produce 100% ripple and low average voltages, resulting in low energy x-ray beam. 3 wave, 6/12 phase generators produce less ripple and higher average voltages. Medium-high frequency generators typically produce ripple < 15%, while constant potential generators produce <2% ripple.
The higher the ripple, the lower the average voltage output and lower the energies of the x-ray beam. This will lead to poor image quality and increased patient dose.
AEC
The AEC (photodetector) is a device that detects the amount of incident radiation on the image detector and automatically stops the x-ray tube when a certain amount of radiation is reached that will give a well-exposed image. It theoretically prevents over- and underexposure that would be a result of varying attenuation e.g. patient body habitus.
It consists of a radiation detector that measures the radiation incident on the image detector (photodiode, SSD, gas ionisation chamber). When a certain present threshold is reached for an exposure, it will shut down the x-ray tube. A backup timer is also in place in case of failure of the AEC.
IOnisation vs excitation
Photostimulable phosphors
Photoelectric effect
Compton scatter
Rayleigh scatter
Scatter
Attenuation
= reduction in x-ray beam intensity by interactions with the imaged materials by:
The linear attenuation coefficient (μ) describes the fraction of photons that is absorbed or scattered by a material per unit distance travelled through it.
It accounts for ALL the causes of attenuation of an x-ray beam as it travels through a material per unit distance.
Note that the linear attenuation coefficient is dependent on density
The mass attenuation coefficient is linear attenuation coefficient / density à μ/p where p = density of the substance
Half value layer
HVL is the thickness of material required to cut transmission of photons by 50%
To calculate the HVL = ln2 / μ = 0.693 / μ
That is:
0.5 = e ^ -μ t
à
t = ln 2/ μ
t = 0.693 / μ
This if a material has a linear attenuation coefficient of 0.5, the HVL = 0.693 / 0.5 = 1.38 cm
Factors increasing attenuation