1.1.6 Projectile Motion Flashcards by Nirwan Gayathra

Q

Projectile motion

A

Motion in two dimensions with horizontal constant velocity and vertical acceleration

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Q

What causes projectile motion?

A

Gravity acting downward

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Q

Air resistance assumption

A

Neglected

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Q

Horizontal motion acceleration

A

0

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Q

Vertical motion acceleration

A

g (9.81 m/s² downward)

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Q

Horizontal velocity

A

Constant

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Q

Vertical velocity

A

Changes with time

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Q

Time in projectile motion

A

Same for horizontal and vertical components

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Q

Initial velocity components

A

u cosθ (horizontal), u sinθ (vertical)

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Q

Horizontal displacement equation

A

s = ut

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Q

Vertical displacement equation

A

s = ut + ½at²

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Q

Vertical velocity equation

A

v = u + at

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Q

At highest point

A

Vertical velocity = 0

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Q

Horizontal velocity at highest point

A

Still constant

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Q

Time to reach maximum height

A

When vertical velocity becomes zero

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Q

What happens to vertical velocity during ascent?

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A

Decreases to zero

Q

What happens during descent?

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A

Increases downward

Q

Shape of trajectory

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A

Parabolic

Q

Range definition

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A

Horizontal distance travelled

Q

Formula for range

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A

R = (u² sin2θ) / g

Q

Condition for maximum range

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A

θ = 45°

Q

Why 45° gives max range?

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A

sin(2θ) is maximum (equals 1)

Q

Projectile symmetry

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A

Time up = time down

Q

Vertical displacement at landing

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A

0 (if same level)

Velocity at landing

Same magnitude as initial but opposite vertical direction

Resultant velocity formula

√(vx² + vy²)

Direction of velocity

tanθ = vy / vx

If angle increases (>45°)

Range decreases

If angle decreases (<45°)

Range decreases

Horizontal + vertical independence

Motions are independent

Thrown horizontally initial vertical velocity

0

Time to fall (horizontal launch)

Depends only on height

Horizontal distance (horizontal launch)

s = ut

Why two objects fall together?

Same vertical acceleration

Key exam idea

Treat horizontal and vertical separately