2015

Question 1

The material composition is the same but its mechanical properties are different in every direction.
A. isotropic material
B. orthotropic material
C. homogeneous material
D. elastic material

Answer 1

B. orthotropic material

Question 2

Refers to the tendency of solid materials to return to their original shape after being deformed when forces are removed.
A. buckling
B. yielding
C. strain hardening
D. elasticity

Answer 2

D. elasticity

Question 3

Refers to the stress at which a material begins to deform plastically.
A. strain hardening
B. buckling
C. yielding
D. rupture

Answer 3

C. yielding

Question 4

ΣM = 0 means:
A. Rotational equilibrium
B. Vertical equilibrium
C. Horizontal equilibrium
D. Dynamic motion

Answer 4

A. Rotational equilibrium

Question 5

Reaction increases when:
A. Load moves closer to support
B. Load moves toward opposite support
C. Span increases
D. Load becomes horizontal

Answer 5

A. Load moves closer to support

Question 6

For a simply supported beam, number of reaction components is:
A. 1
B. 2
C. 3
D. 4

Answer 6

B. 2

Question 7

ΣM=0 about A eliminates which force?
A. A
B. B
C. P
D. Self-weight

Answer 7

A. A

Question 8

Reaction is highest where load is:
A. nearest
B. farthest
C. midpoint
D. nowhere

Answer 8

A. nearest

Question 9

Determinate frame has equilibrium equations:
A. 1
B. 2
C. 3
D. 6

Answer 9

C. 3

Question 10

Reaction direction always opposes:
A. Moment
B. Load
C. Force in members
D. Friction

Answer 10

B. Load

Question 11

Which increases reaction at a support?
A. Load moves toward it
B. Load moves away
C. Beam becomes shorter
D. Beam becomes lighter

Answer 11

A. Load moves toward it

Question 12

If tensions in two cable segments are equal and sag is same on both sides, the load must be located:
A. Anywhere between the supports
B. At midspan
C. At one support
D. At quarter points

Answer 12

B. At midspan

Question 13

Symmetry in structures usually implies:
A. Different reactions
B. Equal internal forces on symmetric parts
C. No vertical reactions
D. Zero cable tension

Answer 13

B. Equal internal forces on symmetric parts

Question 14

For a symmetric cable with central point load, vertical reactions at A and B are:
A. W and 0
B. 0 and W
C. W/2 and W/2
D. 2W and 2W

Answer 14

C. W/2 and W/2

Question 15

As sag d decreases (flatter cable) for same W & span, the horizontal component H will:
A. decrease
B. increase
C. stay constant
D. become zero

Answer 15

B. increase (flatter=mas malaki H)

Question 16

For a given H, increasing sag d will do what to tension T?
A. increase T
B. decrease T
C. same
D. can’t tell

Answer 16

B (mas matarik → actually T grows with tan, but for fixed H & geometry, bigger d usually increases vertical component; careful — but key idea: for same load & span, more sag = less tension

Question 17

Vertical equilibrium at C is expressed as:
A. 𝐻1+𝐻2=𝑊
B. T1​+T2​=W
C. V1​+V2​=W
D. V1​−V2​=W

Answer 17

C. V1​+V2​=W

Question 18

n small-sag approximations, each cable segment between support and lowest point is treated as:
A. circular arc
B. parabola
C. straight line
D. catenary

Answer 18

C. straight line

Question 19

Exact cable shape under uniform self-weight is:
A. circle
B. catenary
C. straight
D. ellipse

Answer 19

B. catenary

Question 20

Increasing sag d (same span and load) generally makes cable tension:
A. increase
B. decrease
C. remain same
D. unpredictable

Answer 20

B. decrease (more sag → more “relaxed” cable).

Question 21

If sag increases while span fixed, the cable length (straight-segment approx) will:
A. decrease
B. stay constant
C. increase
D. go to zero

Answer 21

C. increase

Question 22

A 30 m span cable has same sag d on both sides. At what distance from A should a point load be placed so that tensions in both segments are equal?
A. 5 m 
B. 10 m 
C. 15 m 
D. 20 m

Answer 22

C. 15 m

Question 23

A 40 m cable with equal sag supports a single load. If the load is placed 10 m from A, which segment will have greater tension?
A. AC (left) 
B. BC (right) 
C. Equal 
D. Not enough data

Answer 23

B. BC (right) (mas maiksi horizontal distance → mas matarik angle → mas mataas tension).

Question 24

For a 24 m span with equal tensions desired, choose correct load position:
A. 8 m 
B. 10 m 
C. 12 m 
D. 16 m from A

Answer 24

C. 12 m

Question 25

If loads are not symmetric, 𝑉𝐶 will generally be: A. always zero B. always equal to 𝐴𝑦 C. nonzero depending on imbalance D. equal to 𝐴𝑥 ​

Answer 25

C. nonzero depending on imbalance

Question 26

For symmetric loading about crown, 𝑉𝐶 is often zero because: A. hinge cancels all forces B. left-half loads equal left support reaction C. 𝐴𝑥 is zero D. 𝐻 is maximum

Answer 26

B. left-half loads equal left support reaction

Question 27

A hinge can transmit: A. moment only B. shear & axial but no moment C. moment & shear but no axial D. nothing at all

Answer 27

B. shear & axial but no moment

Question 28

Vertical reactions depend primarily on: A. rise 𝐻 only B. horizontal loads only C. magnitude & positions of vertical loads D. hinge type only

Answer 28

C. magnitude & positions of vertical loads

Question 29

If loading & geometry are symmetric about midspan, then: A. 𝐴𝑦=𝐵𝑦 B. 𝐴𝑥=0 C. 𝑉𝐶≠0 always D. 𝑀𝐶 is max

Answer 29

A. 𝐴𝑦=𝐵𝑦

Question 30

With purely vertical loads, Σ𝑉=0 ΣV=0 gives: A. 𝐴𝑥+𝐵𝑥=Σ𝑃 B. 𝐴𝑦+𝐵𝑦=Σ𝑃 C. 𝐴𝑦−𝐵𝑦=Σ𝑃 D. 𝐴𝑥=𝐵𝑦

Answer 30

B. 𝐴𝑦+𝐵𝑦=Σ𝑃

Question 31

In a three-hinged arch, the bending moment at crown hinge C is: A. max B. min C. zero D. depends on load

Answer 31

C. zero

Question 32

Why is 𝐴𝑥=𝑀𝐶/𝐻 valid? A. shear at C is zero always B. moment at C must be zero C. axial force is zero D. reactions are equal always

Answer 32

B. moment at C must be zero

Question 33

If rise 𝐻 increases (same loads), 𝐴𝑥 will: A. increase B. decrease C. unchanged D. becomes zero

Answer 33

B. decrease

Question 34

When is the vertical reaction at crown hinge 𝑉𝐶 = 0? A. Always, regardless of loading B. Only when rise 𝐻=0 C. When loading and geometry are symmetric about the crown D. When there is at least one horizontal load

Answer 34

C. When loading and geometry are symmetric about the crown

Question 35

Why we can use 𝐴𝑥=𝑀𝐶/𝐻? Because for a three-hinged arch: A. Shear at crown is always zero B. Moment at crown hinge must be zero C. Axial force is zero everywhere D. Vertical reactions are always unequal

Answer 35

B. Moment at crown hinge must be zero

Question 36

Key property of a three-hinged arch At the crown hinge 𝐶, the bending moment is always: A. Maximum B. Minimum C. Zero D. Equal to 𝐴𝑥𝐻

Answer 36

C. Zero