Chapter 5 - Test ( Crystal structure ) Flashcards

(38 cards)

1
Q

What are unit cells

A

Bonds that occur between atoms, molecules, or ions in an ordered arrangement form the basic building block

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2
Q

Explain unit cells fully

A
  • Is the smallest group of atoms, ions or molecules that, when repeated at regular intervals in three dimensions will produce the LATTICE POINTS of a crystal system / structure / Lattice
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3
Q

What are lattice points

A

A point in space where atoms, ions or molecules are positioned in a repeating pattern to form a crystal lattice

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4
Q

Explain the lattice parameter

A
  • Is the length between two points on the corners of a unit cell
  • If two sides are equal, such as in a tetragonal lattice, then the lengths of the two lattice parameters are designated a and c , with b omitted
  • Different lattice parameters of unit cell form different crystal systems
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5
Q

What are the 7 crystal lattice systems

A
  • Cubic
  • Tetragonal
  • Orthorhombic
  • Rhombohedral
  • Hexagonal
  • Monoclinic
  • Triclinic
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6
Q

Explain the cubic crystall lattice system

A
  • a=b=c,
  • α = β = γ = 90°
  • Three sides are equal, so the three lattice parameters are designated ONLY as a with b, c omitted

OR

b and c are also considered to be “a”

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7
Q

Explain the Tetragonal crystall lattice system

A

a = b ≠ c

α = β = γ= 90°

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8
Q

Explain the Orthorhombic crystall lattice system

A

a ≠ b ≠ c

α = β = γ= 90°

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9
Q

Explain the Rhombohedral crystall lattice system

A

a = b = c

α = β = γ ≠ 90°

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10
Q

Explain the Hexagonal crystall lattice system

A

a = b ≠ c

α = β = 90°, γ = 120°

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11
Q

Explain the Monoclinic crystall lattice system

A

a ≠ b ≠ c

α = γ = 90°, β ≠ 90°

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12
Q

Explain the Triclinic crystall lattice system

A

a ≠ b ≠ c

α ≠ β ≠ γ

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13
Q

What is crystal structure

A
  • It is ordered OR repeating arrangement of atoms / ions / molecules [consider these as particles] in a crystalline material
  • Structure refers to the internal arrangement of particles and not the external appearance of the crystal
  • However, these are not entirely independent since the external appearance of a crystal is often related to the internal arrangement
  • For example, crystals of cubic rock salt (NaCl) are physically cubic in appearance
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14
Q

What are the types of cubic structures

A
  • Simple cubic
  • Body centered cubic
  • Face centered cubic
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15
Q

What are miller indices

A

Planes in a crystal can be specified using a notation called Miller indices

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16
Q

Explain the Miller indices

A
  • The Miller index is indicated by the notation [hkl] where h, k, and l are reciprocals of the plane with the x, y, and z axes
  • Miller indices directions may be grouped in families
  • Individual Miller indices are given in parentheses (hkl), while braces {hkl} are placed around the indices of a family of planes

For example, (001), (100), and (010) are all in the {100} family of planes, for a cubic lattice

17
Q

What are the steps To obtain the Miller indices of a given plane

A

1.The plane in question is placed on a unit cell

2.Its intercepts with each of the crystal axes are then found

3.The reciprocal of the intercepts are taken

4.These are multiplied by a scalar to insure that is in the simple ratio of whole numbers

18
Q

Desribe the crystal structure

A
  • Consideration of several unit cells, the arrangement of the atoms with respect to each other, the number of other atoms
    they in contact with, and the distances to neighboring atoms, often will provide a better understanding
  • A number of methods are available to describe extended solid-state structures
  • The most applicable with regard to elemental and compound semiconductor, metals and the majority of insulators is the CLOSE PACKING APPROACH
19
Q

What is closed packing

A

Atoms (ions) are arranged so as to have the maximum density

20
Q

What are the closed packing structures

A
  • Hexagonal Close Packing
  • Cubic Close Packing
21
Q

Explain “ The most efficient way for equal sized spheres to be packed in
two dimensions “

A
  1. It can be seen that each sphere (the dark gray shaded sphere) is surrounded by, and is in contact with, six other spheres (the light
    gray spheres )
  2. Each sphere is in contact with six other spheres the maximum possible is the spheres are the same size, although lower density
    packing is possible
  3. Close packed layers are formed by repetition to an infinite sheet

Within these close packed layers, three close packed rows are present, shown by the dashed lines

22
Q

Explain the Hexagonal Close Packing

A
  • If two close packed layers A and B are placed in contact with each other so as to maximize the density, then the spheres of layer B will rest in the hollow (vacancy) between three of the spheres in layer A
  • Atoms in the second layer, B (shaded light gray), may occupy one of two possible positions but not both together or a mixture of each
  • If a third layer is placed on top of layer B such that it exactly covers layer A, subsequent placement of layers will result in the following
    sequence …ABABAB…. This is known as hexagonal close packing or hcp
23
Q

Explain the Cubic Close Packing

A
  • Two close packed layers are stacked
  • Third layer (C) is placed such that it does not exactly cover layer A
  • The packing sequence will be…ABCABCABC….
  • The unit cell of cubic close packed structure is actually that of a face-centered cubic (fcc) Bravais lattice
  • In the fcc lattice the close packed layers constitute the {111} planes
  • As with the hcp lattice packing fraction in a cubic close packed (fcc) cell is 74.05%
24
Q

Packing Fraction / Packing Density

A

The packing fraction or density is derived by assuming that each atom is a hard sphere in contact with its nearest neighbours

25
Explain the Determination of the packing fraction
- By calculating the number of whole spheres per unit cell (2 in hcp), the volume occupied by these spheres, and a comparison with the total volume of a unit cell - The number gives an idea of how “open” or filled a structure is - The “packing fraction” OR “packing density”: a hexagonal close packed unit cell is 74.05% of the total volume is occupied
26
What is a co-ordination number
- Of an atom or ion within an extended structure is the number of nearest neighbor atoms (ions of opposite charge) that are in contact with it - A slightly different definition is often used for atoms within individual molecules: the number of donor atoms associated with the central atom or ion - However, this distinction is rather artificial, and both can be employed
27
What are the coordination numbers for metal atoms in a molecule or complex
Are commonly 4, 5, and 6, but all values from 2 to 9 are known and a few examples of higher coordination numbers have been reported
28
What are defects
Ordinarily exist in equilibrium between the crystal lattice and its environment
29
What are the types of defects
1. Point defects are associated with a single crystal lattice site 2. Extended defects occur over a greater range
30
What are types of point defects
- Vacancy - Interstitial impurity - Self-interstitial - Substitution impurity - Frenkel defect
31
Explain the vacancy point defect
Missing atom at a certain crystal lattice position
32
Explain the interstitial impurity point defect
Extra impurity atom in an interstitial position
33
Explain the Self-interstitial point defect
Extra atom in an interstitial position
34
Explain the Substitution impurity point defect
Impurity atom, substituting an atom in crystal lattice
35
Explain the Frenkel defect point defect
Extra self-interstitial atom, responsible for the vacancy nearby
36
Frenkel defect found in AgCl
- Difference between phosphorus-doped and gallium doped silicon semiconductors? - AgCl has a Frenkel defect because Ag+ is small enough to fit into interstitial vacant positions - As a result of the large size difference between the ions Ag+ and Cl– and Ag+ occupies voids - Phosphorus-doped semiconductors produced n-type semiconductors, whereas gallium-doped silicon produced p-type semiconductors
37
Number of atoms in fcc unit cel for Frenkel defect found in AgCl
- There are 8 atoms at each of the 8 corners and 6 atoms at each of the 6 face centres in this unit cell - Since each corner contributes 1/8th of an atom to the unit cell, the number of atoms = 1/8 × 8 = 1 - Since each face centre contributes half an atom to the unit cell, the number of atoms = 1/2 × 6 = 3 ∴ The total number of atoms in a fee unit cell is 1 + 3 = 4 As a result, the volume of the unit cell equals the volume of four atoms
38
Point flaws appear when...
1. One or more crystal atoms are missing from their corresponding lattice site 2. The atom(s) is shifted from its corresponding lattice site to the crystal’s interstitial position 3. The interstitial position in the crystal lattice is occupied by a foreign atom or atoms 4. A foreign atom replaces the crystal’s original atom