A-level Maths (pure) > Chapter 9 - Differentiation > Flashcards
y=sinkx
kcoskx
y=coskx
-ksinkx
y=e^kx
ke^kx
y=lnx
1/x
y = a^kx
a^kx klna
chain rule
dy/dx = dy/du * du/dx
product rule (y=uv)
dy/dx = u(dv/dx) + v(du/dx)
quotient rule (y=u/v)
dy/dx= (v(du/dx)-u(dv/dx))/v^2