Explain the equilibrium law.
The equilibrium states that for the equilibrium
aA +bB cC + dD
Kc= [C]^c[D]^d/[A]^a[B]^b
Kc is the equilibrium constant in terms of concentrations.
The equilibrium concentration of each product and reactant is raised to the power of its balancing number in the overall equation.
Dinitrogen tetroxide, N2O4 is a colourless gas.Nitrogen dioxide, NO2, is a dark brown gas.
N2O4 and NO2 are linked by a reversible reaction.
If N2O4 is placed in a sealed container explain what happens to the concentrations of the reactants/products till they reach dynamic equilibrium.
If N2O4 is placed in a seal container:
-N2O4 molecules start to decompose into NO2 molecules- because there will be very few NO2 molecules present, the reverse reaction will take place slowly.
As the reaction proceeds:
Eventually, a dynamic equilibrium is established:
What are the units for Kc?
The units for Kc expressions can be worked out afresh after each Kc expression. Each concentration term in the Kc expression is replaced by its units.
What does the magnitude of Kc indicate?
The magnitude of Kc indicates the extent of a chemical reaction.
What happens in an equilibrium where Kc > 1?
- The products on the right-hand side predominate at equilibrium.
What happens in an equilibrium where Kc <1?
- The reactants on the left-hand side predominate at equilibrium.
What does the value of Kc change with?
Kc only changes with temperature.
But the way that Kc changes is linked to Change in H.
Is Kc affected by changes in pressure and concentration?
No
Explain why Kc is unaffected by changes in concentration.
If a certain product is added to an equilibrium the concentrations change and the equilibrium position shifts to restore to the Kc value.
Explain why Kc is unaffected by changes in pressure.
If the pressure in an equilibrium is doubled the concentrations of the products and reactants will double.
This will change the equilibrium constant and the equilibrium constant will shift to restore the concentrations back to normal.
How does the presence of a catalyst affect Kc?
Catalysts affect the rate of a chemical reaction, but not the position of equilibrium. We reach the equilibrium more quickly with a catalyst.
What does a large value for Kc mean?
A large value for k means a fast rate of reaction.