knee

Question 1

• placing the femoral epicondyle parallel with the IR for a true AP projection
• CR directed to a point 1/2 inch
  inferior to the patellar apex
• shows an AP projection of the knee structures

Answer 1

AP Projection

Question 2

thin pelvis

Answer 2

18cm and below, 3-5 degrees caudad

Question 3

average size

Answer 3

19-24 cm, 0 degrees

Question 4

large pelvis

Answer 4

25cm and above, 3-5 degrees cephalad

Question 5

• flex knee 20-30 degrees
• patella perpendicular to the plane of IR
• CR knee joint 1 inch distal to the medial epicondyle at an angle of 5 to 7 degrees cephalad
• shows a lateral image of the distal end of the femur, patella, knee joint, proximal ends of the tibia and fibula, and adjacent soft tissue

Answer 5

LATERAL PROJECTION
Mediolateral

Question 6

• arthritic knees.
• stand straight with knees fully extended and weight equally distributed on the feet
• CR 1/2 inch below the apices of the patellae
• shows joint spaces of the knee

Answer 6

AP PROJECTION
WEIGHT-BEARING METHOD

Question 7

• flex knees to place femurs 45 degrees
• CR horizontal and perpendicular to the center of IR
• useful for evaluating joint space narrowing and demonstrating articular cartilage disease

Answer 7

PA PROJECTION
ROSENBERG METHOD
WEIGHT-BEARING

Question 8

• externally rotate the limb 45 degrees
• CR 1/2 inch inferior to the patellar apex
• shows an AP oblique projection of the laterally rotated femoral condyle, patella, tibial condyles, and head of the fibula.
• Fibula superimposed over the lateral half of the tibia.

Answer 8

AP OBLIQUE PROJECTION
Lateral rotation

Question 9

• medially rotate the limb at 45 degrees
• shows AP oblique projection of the medially rotated femoral condyles, patella, tibial condyles,
• proximal tibiofibular joint, and head of the fibula

Answer 9

AP OBLIQUE PROJECTION
Medial rotation