Net Ionic Equations

Question 1

Net Ionic: Displacements

Answer 1

• Aqueous reactants form ionic bonds and turn into solid products (precipitate out of solution) and participate in reaction
• Spectators ions do not do anything and are not involved in reaction
• Solutions in the word problem will always have aqueous reactants, solubility table is not used

Question 2

Total Ionic Equation

Answer 2

• Aqueous solutions are broken up into their ions
• Balance the ions per compounds
• Do not break up solids
• Cancel out ions that are the exact same from recant to product
• Same number and states
• The ions cancel out are spectator ions

Question 3

Net Ionic Equation

Answer 3

• After simplifying and canceling our spectator ions, you are left with the equation reacting
• Should only be the ions that make up precipitate
• Should not balance at the end, it is wrong if you need to

Question 4

Qualitative analysis

Answer 4

• Seeing something happen or not happening
• Adding something to create a precipitate
• Look at the solubility table to see what form a solid
• The ions need to be added through a ionic compound (do not exist as ions in nature)
• The ionic compounds must have a cations that is soluble and does not form a precipitate with anion in solutions (we have no info about them)
• Sodium, potassium and ammonium are soluble under all conditions
• If a given ions is in the solution, it will form a precipitate, if not the solution remains transparent

Question 5

1+ cations in solution

Answer 5

• Chose a ion that precipitates one of the cations, not both
• If precipitate occurs, filter it and then add an ion to see if the second cation will precipitate
• Chose two same cations for ionic compounds
• Use prodeeral flow charts
• Making the ionic compounds do not need solubility table