Rates Flashcards

(30 cards)

1
Q

What is the rate equation and meaning of each symbol

A

Rate = k x [A]^a x[B]^b x[C]^c

k= rate constant
[A] = concentration of reactant A (mol dm-3) etc for B and C
a= order with respect to A. Etc for b and c (shows the number of particles involved in the rate determining step) (there is no link between balancing numbers and order numbers)

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2
Q

What does a 0 order reactant mean

A

The conc of that reaction had no effect on the rate of the reaction

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3
Q

What does a 1st order reactant mean

A

The rate of reaction is directly proportional to the concentration of the reactant

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4
Q

What does a second order reactant mean

A

The rate of the reaction increases exponentially with the conc of the reactant

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5
Q

What it’s important about the rate constant

A

It is only constant for a given reaction at a given temperature

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6
Q

How do you calculate the units of k

A

Units of rate / (units of concentration)^overall order

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7
Q

What is the overall order

A

The sum of all the individual orders

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8
Q

describe the zero order conc/time graph

A

straight line with a negative gradient
value of k’ is equal to the gradient

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9
Q

describe the first order conc/time graph

A

curve with a negative gradient

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10
Q

describe the second order conc/time graph

A

steeper curve then first with negative gradient

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11
Q

describe the zero order rate/conc graph

A

straight horizontal line

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12
Q

describe the first order rate/conc graph

A

straight diagonal line with positive gradient

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13
Q

describe the second order rate/conc graph

A

exponential curve

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14
Q

what is the isolation method

A

one of the reactants is isolated by putting the conc of all the others into vast excess so that any change in rate is due only to the conc of the reactant not in vast excess

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15
Q

how do you determine the order from the isolation method

A

use the conc/time graphs

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16
Q

if the order for a given reactant is first order that what is the rate of reaction directly proportional to

A

the concentration

17
Q

what is special about a first order reaction conc/time graph

A

the half life is constant

18
Q

how can you calculate the k’ from the first order conc/time graph

A

draw a tangent to the curve at a particular concentration and calculate its gradient(rate).
substitute into rate equation r=k’[A]^1.
OR k’=ln2/half life

19
Q

for a second order what is the rate of reaction directly proportional to

A

the square of the concentration

20
Q

what does the half life do in a second order conc/time graph

A

it is not constant, it has an increasing half life

21
Q

experimental techniques that can be used for measuring the concentration of a reactant

A

colorimetry
measuring the volume of gas
measure a change in mass of the reaction

22
Q

how does the initial rate method work

A

the initial rate at the start of the reaction is measured before the conc of any reactants has had the chance to change.
the conc of one of the reactants is then changed by a specific amount.
the ratio of the initial rates are then compared and the orders can be worked out

23
Q

what equation do you need for the initial rate method and how do you select the experiments to use

A

(conc (exp a)/conc (exp b))^order= initial rate (exp a/initial rate (exp b)

find experiments where only one reactants conc changes

24
Q

what do the order numbers say about the rate determining step

A

how many moles of each substance are in it

25
how do you find the units for k
use the equation k=rate/[A]^a [B]^b [C]^c
26
how can you rearrange Arrhenius equation
lnk=-(Ea/R)(1/T) + lnA T has to be in kelvin
27
how can you use arrhenius equation on a graph
if the rate constant is measured at different temperatures a plot of lnk against 1/T a straight line should be produced with a gradient of -Ea/R
28
which is the rate determining step
the slowest step
29
if trying to work out the order and your given the conc of 2 reactants and the initial rate in multiple exp what do you look for
eg what doubling the conc does to the rate
30
how do you work out the half life
work out the time for the conc to be halved do this again for the conc value you have just worked out for another half life