Superposition Flashcards

(21 cards)

1
Q

What is an antinode

A

Maximum amplitude (in phase)

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1
Q

What is a node

A

Minimum amplitude (anti-phase)

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1
Q

What is the fundamental mode

A

1st harmonic

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1
Q

How is a stationary wave formed in a flute

A

Incident and reflected waves are superimposed at specific frequencies

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2
Q

What are closed ends

A

Nodes (Min amplitude)

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2
Q

What are open ends

A

Antinodes (Max amplitude)

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2
Q

What is a pressure node

A

Displacement antinode

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2
Q

What is a pressure antinode

A

Displacement node

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3
Q

Difference between constructive and destructive interference

A

Path difference
C: n(wavelength)
D: (n+0.5)(wavelength)

Phase difference
C: Even no. pi
D: Odd no. pi

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3
Q

Explain how a bright fringe is observed

A
  • Path difference of the 2 waves is n(wavelength)
  • 2 waves leave the 2 slits in phase and arrive in phase
  • Constructive interference occurs
  • Bright fringe observed
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3
Q

Explain how a dark fringe is observed

A
  • Path difference of the 2 waves is (n+0.5)(wavelength)
  • 2 waves leave the 2 slits in phase and arrive in anti-phase
  • Destructive interference occurs
  • Dark fringe observed
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3
Q

Formula for double slit interference

A

x=D(wavelength)/a

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3
Q

What are the assumptions for double slit interference

A
  • wavelength «_space;a «_space;D
  • Small angle approximation holds
  • Light rays are approximately parallel
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4
Q

Default number of diffraction grating lines per metre

A

5x10^5

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5
Q

Condition for 2 diffraction patterns to be distinguishable

A

Central maximum of one diffraction patterns must lie on first minimum of the other diffraction pattern

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6
Q

Explain why stationary waves on strings only occur at specific frequencies

A
  • Stationary wave is formed only when ends of string are nodes (anti-phase, min amplitude)
  • Only specific wavelengths and hence specific frequencies matching natural frequency of string can form stationary waves
7
Q

Why is it impossible to observe interference fringes between light beams plane polarised

A
  • Resultant intensity is always constant
  • No destructive regions
  • No interference pattern observed
8
Q

Explain changes when intensity of one light on one slit is reduced in double slit

A
  • Intensity of bright fringe decreases
  • Intensity of dark fringe increases
9
Q

Explain changes when slit width is reduced in double slit

A
  • No change in slit separation
  • Intensity of bright fringe decreases
  • Intensity of dark fringe remains same
  • No. of fringes increases
10
Q

Explain why when white light incident on single slit, central fringe is coloured at edges and has white central region

A
  • White light consists of various wavelengths of light
  • Different wavelengths of light have different angles of diffraction
  • At centre all wavelengths undergo constructive interference to form central white region
11
Q

Why do intensities of double slit fringes decrease further from central maxima

A
  • Waves exiting double do not behave as point sources