Elementary charge (e-) in coulombs
1.6 x 10^-19
F(E) =
K |Q||q|/r^2
K =
9 x 10^9
Work eqn using electric potential
W=(charge)(change in potential) = change in PE
Capacitance ________ when plates are closer together
Increases
Capacitance ________ when plate area is smaller
Decreases
Charge stored in a capacitor eqn
Q= CV
Potential energy in a capacitor
(1/2)QV^2 = .5 C V^2 = Q^2/(2C)
Area under Q vs V graph
Electric field for planes of charge capacitors
E = V/d
Dielectric impact on capacitance
C’= kC