Identify the range of the following function
{-5, -π} ∪ (0, 7)
True or false?
(f∘f-1)(x) = (f-1∘f)(x)
True.
It is commutative in this case. However, note it is not always commutative like (f∘g)(x) may not be equal to (g∘f)(x) when g and f are different functions.
Sketch the inverse of a sin function
Initially, you cannot get an inverse of a sin as it is not one-to-one. But when you restrict the domain, it is possible which gives you the arcsin(x) function
Sketch the inverse of a cosine function
Initially, you cannot get an inverse of a cos as it is not one-to-one. But when you restrict the domain, it is possible which gives you the arccos(x) function
Sketch the inverse of the tan function
What is tan(pi/4)
1
What is tan (pi/6)
1/sqrt(3) = sqrt(3)/3
What is tan (pi/3)
sqrt(3)
Given a sequence {an}7n=0
When does the sequence start and end?
Starts at a0 and ends at a7
What can be said about convergent sequences?
Convergent sequences have a limit.
It can be said that the sequence will ‘converge’ to the limit
Determine if the following sequence is convergent or divergent?
True or false?
Since both cos(nπ) and sin(nπ) alternate, they are both divergent.
False
True or false?
Adding two limits that are divergent will always give a divergent limit.
False.
Identify if the following sequence converges or not.
{an}=rn
for |r|<1
Converges to 0
|r|<1 basically means -1<r<1.
And so it will become some fraction of 1 (1/2, -1/3, 1/4, etc.). Raising these numbers to higher powers will make them become closer to zero whether they are negative or positive (the denominator will get larger and larger)
Identify if the following sequence converges or not.
{an}=1n
Converges to 1
Identify if the following sequence converges or not.
{an}=(-1)n
Divergent
{an}=1,-1, 1,-1, 1,-1, 1,-1…
Identify if the following sequence converges or not.
{an}=rn
for |r|>1
Sequence is divergent
For any number larger than 1, an will get larger as it will be raised to larger powers (either negative way or postive way). And so the limit would be infinity meaning it D.N.E
Evaluate the following limit
lim=1. Converges to 1
Notice the 1/n exponential. So as n gets larger, exponent will get closer to 0. And so c1/n will get closer to 1 (c0=1)
Evaluate the following limit
Converges to 0. Note that as n gets larger, the demonimator (nr) will aproach a large number. And 1 divided by a larger and larger number will become closer and closer to 0
True or false?
The following limit is known as an indeterminate
False.
Recall that an indeterminate is when there is ‘competition’ where the number wants to get larger and smaller at the same time such as: (an)/n
Evaluate the following limit
1
Note that the base, n gets larger but the index, 1/n gets smaller. And so there is a competition going on. So it is either the limit aproaches infinity (base wins the competition) or the limit aproaches 1 (index wins the competition, 1/n aproaches 0). You just have to remember that the index wins
True or false.
The following is an example of an indeterminate
True.
There is a ‘competition’ going on. The base, n gets larger but the index, 1/n gets smaller
Evalutate the following limit
0
As n gets larger, the denominator will get larger, and the number will get smaller and smaller (aproaching 0)
Evaluate the following limit
0
This is an example of an indeterminate. The numerator will try to make the limit to get larger and larger as n increases while the denominator will try to make the limit smaller as n increases. The question is, who will win. In this case, factorials have a greater rate of change (on average) and so the denominator will win and cause the limit to aproach 0.