cosh, sinh, tanh - what creates 1? List all 3
c - s
State in e: cosh, sinh, tanh
1/2 (ex + e-x)
1/2 (ex - e-x)
(ex - e-x) / (ex + e-x)
cosh(A±B), sinh(A±B), tanh(A±B)
c – cAcB ± sAsB
s – sAcB ± cAsB
t – tA ± tB / 1 ± tAtB
State in the normal functions: cosh, sinh, tanh
cos ix = cosh x
sin ix = i sinh x
tan ix = i tanh x
graph cosh, sinh, tanh, sinh-1, cosh-1, tanh-1
c - (0, 1) close to ex
s - gradient 1 at 0, pass origin
t - limits at |y|=1, pass origin
s - long s, no limits
c - long c, no real value where cosh x < 1
t - limits at |x|=1
Rewrite sinh-1, cosh-1, tanh-1
s - ln(x + √x2+1)
c - ±ln(x ± √x2-1)
t - 1/2 ln(1+x / 1-x)
Draw ellipse
Write equation and key parts of graph
Write in terms of trigo functions
A = πab
(x/a)² + (y/b)² = 1
x = a cos θ + x0
y = b sin θ + y0
Draw hyperbola
When does it face each way
key identifiers
(x/a)² - (y/b)² = 1
x = ± r cosh θ )(, y no ±
y = ± r sinh θ U
if x² > 0 )(
y = bx/a
Write circle in trigo
x0 + rcos
y0 + rsin
Find roots z if cos z = 2
cos(x+iy) = cosx cosh y - i sin x sinh y
real -> 2
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