prokaryotes
eukaryotes
Scenario: Compare how E. coli (a bacterium) and Saccharomyces cerevisiae (baker’s yeast)
organize their cellular biochemistry.
Step 1: Identify key structural differences
Scenario: Compare how E. coli (a bacterium) and Saccharomyces cerevisiae (baker’s yeast)
organize their cellular biochemistry.
Step 2: Analyze biochemical implications
Scenario: Compare how E. coli (a bacterium) and Saccharomyces cerevisiae (baker’s yeast)
organize their cellular biochemistry
Step 3: Compare specific biochemical processes
Step 4: Predict outcomes
Scenario: Compare how E. coli (a bacterium) and Saccharomyces cerevisiae (baker’s yeast)
organize their cellular biochemistry
Background: Prokaryotes have DNA in a nucleoid region (not membrane-bound), while
eukaryotes have DNA enclosed in a nucleus with nuclear pores.
Advantage 1:
Allows mRNA processing and quality control (capping, splicing, poly-A tail) before translation.
Advantage 2:
Provides greater regulation of gene expression, so proteins are made only when and where needed.
Background: Prokaryotes have DNA in a nucleoid region (not membrane-bound), while
eukaryotes have DNA enclosed in a nucleus with nuclear pores.
Explanation (why this works in prokaryotes):
Prokaryotes lack a nucleus, so ribosomes can bind to mRNA while it is still being transcribed.
In eukaryotes, DNA is enclosed in the nucleus, while ribosomes are in the cytoplasm. mRNA must first be fully transcribed and processed, then exported through nuclear pores, so transcription and translation cannot occur simultaneously.
Background: Prokaryotes have DNA in a nucleoid region (not membrane-bound), while
eukaryotes have DNA enclosed in a nucleus with nuclear pores.
mRNA processing:
Protects mRNA from degradation (5′ cap, poly-A tail)
Ensures correct protein sequence (splicing removes introns)
Helps ribosomes recognize mRNA for efficient translation
Without processing, mRNA would be unstable or produce incorrect proteins.
Background: Prokaryotes have DNA in a nucleoid region (not membrane-bound), while
eukaryotes have DNA enclosed in a nucleus with nuclear pores.
Loss of gene regulation
Proteins meant for the cytoplasm could enter the nucleus randomly
RNA and enzymes could move uncontrollably
Increased risk of DNA damage and improper gene expression
Overall: the nucleus would lose functional control.
Background: Prokaryotes have DNA in a nucleoid region (not membrane-bound), while
eukaryotes have DNA enclosed in a nucleus with nuclear pores.
Despite the advantages, the nucleus has costs. What is ONE disadvantage of nuclear
compartmentalization?
Disadvantage:
It slows down gene expression because transcription, processing, and transport must occur before translation.
The nucleus increases regulation and accuracy of gene expression but at the cost of speed and energy efficiency.
Background: Eukaryotic cells have specialized organelles (mitochondria, ER, Golgi, lysosomes,
peroxisomes), while prokaryotes lack these structures.
Background: Eukaryotic cells have specialized organelles (mitochondria, ER, Golgi, lysosomes,
peroxisomes), while prokaryotes lack these structures.
ysosomal compartmentalization is essential because it protects the rest of the cell from the lysosome’s destructive enzymes.
Lysosomes contain acidic hydrolase enzymes that function optimally at low pH (~5). By enclosing these enzymes in a membrane-bound compartment and maintaining an acidic environment with proton pumps, the cell ensures that:
The enzymes are active only inside the lysosome
They do not digest cellular components in the cytoplasm, which is near neutral pH
Any enzymes that leak into the cytoplasm become largely inactive
Without this compartmentalization, lysosomal enzymes could damage or destroy essential cellular structures, threatening cell survival.
In short: compartmentalization allows safe, controlled breakdown while protecting the rest of the cell.
Background: Eukaryotic cells have specialized organelles (mitochondria, ER, Golgi, lysosomes,
peroxisomes), while prokaryotes lack these structures.
Maintaining a different calcium concentration in the ER is useful because it allows the cell to use Ca²⁺ as a fast, tightly controlled signaling molecule.
The ER acts as a calcium storage reservoir, keeping Ca²⁺ levels low in the cytoplasm. When a signal is received, calcium channels in the ER membrane open and rapidly release Ca²⁺ into the cytoplasm, creating a brief calcium spike. This sudden increase activates specific proteins and pathways involved in processes such as muscle contraction, secretion, and metabolism.
After signaling, calcium is pumped back into the ER, turning the signal off. This compartmentalization allows calcium signals to be rapid, localized, and reversible, preventing constant or uncontrolled activation.
Background: Eukaryotic cells have specialized organelles (mitochondria, ER, Golgi, lysosomes,
peroxisomes), while prokaryotes lack these structures
These reactions must be compartmentalized because hydrogen peroxide (H₂O₂) is highly reactive and damaging to cellular components.
Peroxisomes isolate enzymes that produce H₂O₂ so that this toxic molecule does not accumulate in the cytoplasm, where it could damage DNA, proteins, and membranes. By keeping both H₂O₂-producing enzymes and catalase inside the peroxisome, the cell ensures that hydrogen peroxide is generated and broken down in a controlled space.
Without compartmentalization, oxidative reactions could cause widespread cellular damage. In short, peroxisomes allow useful oxidative chemistry while protecting the rest of the cell.
Background: Eukaryotic cells have specialized organelles (mitochondria, ER, Golgi, lysosomes,
peroxisomes), while prokaryotes lack these structures.
☑ 30–50%
n a typical eukaryotic cell, membrane-bound organelles (nucleus, ER, mitochondria, Golgi, lysosomes, etc.) occupy a large fraction of the cell’s interior, but not most of it. The cytosol still makes up a significant portion, so values below 30% are too small and above 50% is usually too high.
What this tells you about the “cost” of compartmentalization
This shows that compartmentalization is expensive for the cell:
Requires large amounts of membrane (lipids + proteins)
Takes up physical space that could otherwise be cytoplasm
Requires energy to maintain gradients (pH, ions, molecules)
Despite these costs, cells keep organelles because the benefits—efficiency, regulation, protection, and specialization—outweigh the space and energy costs.
Bottom line: compartmentalization is costly, but it dramatically improves cellular control and function.
Background: Prokaryotes are typically 1-10 μm, while eukaryotes are 10-100 μm. Cell size is
limited by the surface area-to-volume ratio.
Decreases
Why:
Volume increases faster than surface area as size increases.
Background: Prokaryotes are typically 1-10 μm, while eukaryotes are 10-100 μm. Cell size is
limited by the surface area-to-volume ratio.
Long or branched shapes increase surface area without greatly increasing volume, helping maintain a high SA/V ratio and allowing efficient nutrient and gas exchange.
As cells get bigger, SA/V ratio decreases, so cells evolve shapes and internal membranes to compensate.
Background: Prokaryotes are typically 1-10 μm, while eukaryotes are 10-100 μm. Cell size is
limited by the surface area-to-volume ratio.
A high SA/V ratio allows faster exchange of nutrients, gases, and wastes across the cell membrane. Cells rely on diffusion, so having more surface area relative to volume makes transport more efficient.
Background: Prokaryotes are typically 1-10 μm, while eukaryotes are 10-100 μm. Cell size is
limited by the surface area-to-volume ratio.
Radius
𝑟
=
1
𝜇
𝑚
r=1μm
Surface area
4
𝜋
𝑟
2
=
4
𝜋
(
1
)
2
=
4
𝜋
≈
12.6
𝜇
𝑚
2
4πr
2
=4π(1)
2
=4π≈12.6μm
2
Volume
4
3
𝜋
𝑟
3
=
4
3
𝜋
(
1
)
3
=
4
3
𝜋
≈
4.2
𝜇
𝑚
3
3
4
πr
3
=
3
4
π(1)
3
=
3
4
π≈4.2μm
3
SA/V ratio
12.6
4.2
≈
3
4.2
12.6
≈3
Large eukaryote (diameter = 20 μm)
Radius
𝑟
=
10
𝜇
𝑚
r=10μm
Surface area
4
𝜋
(
10
)
2
=
400
𝜋
≈
1256
𝜇
𝑚
2
4π(10)
2
=400π≈1256μm
2
Volume
4
3
𝜋
(
10
)
3
=
4000
3
𝜋
≈
4189
𝜇
𝑚
3
3
4
π(10)
3
=
3
4000
π≈4189μm
3
SA/V ratio
1256
4189
≈
0.3
4189
1256
≈0.3
Which has a higher SA/V ratio?
☑ Prokaryote
Background: Prokaryotes are typically 1-10 μm, while eukaryotes are 10-100 μm. Cell size is
limited by the surface area-to-volume ratio.
Eukaryotic cells increase internal surface area using membranes such as:
Endoplasmic reticulum
Mitochondrial cristae
Golgi membranes
These structures allow efficient reactions and transport inside the cell, even though the external SA/V ratio is low.
Scenario: Antibiotics like penicillin target bacterial cell walls, while antibiotics like tetracycline
target bacterial ribosomes. These drugs kill bacteria but don’t harm human cells.
Penicillin targets peptidoglycan, a key component of bacterial cell walls. Human cells do not have cell walls—only plasma membranes—so penicillin has no target in human cells and does not affect them.
Scenario: Antibiotics like penicillin target bacterial cell walls, while antibiotics like tetracycline
target bacterial ribosomes. These drugs kill bacteria but don’t harm human cells.
Yes
Explanation:
Mitochondria evolved from bacteria (endosymbiotic theory) and contain 70S ribosomes, which are similar to bacterial ribosomes. Because of this similarity, tetracycline can sometimes interfere with mitochondrial protein synthesis, especially at higher doses or with prolonged use.
Scenario: Antibiotics like penicillin target bacterial cell walls, while antibiotics like tetracycline
target bacterial ribosomes. These drugs kill bacteria but don’t harm human cells.
Fatigue or muscle weakness (due to reduced ATP production)
Other acceptable examples:
Neurological symptoms (e.g., dizziness)
Gastrointestinal distress
Lactic acidosis (in severe cases)
These occur because mitochondria are responsible for cellular energy production.