Define Capacitance
charge stored per unit potential difference
What is a capacitor
2 metalllic plates separated by an insulated, used to separate charge
what is the equation for capacitance
C = Q/V
C - capacitance in F (farads)
What is the unit farad
A capacitor has a capacitance of 1 F when its plates store 1 coulomb of charge per volt across the plates
When initially charging a capacitor what happens on the positive side of the circuit
Electrons on the plate connected to the positive terminal are attracted to it, so they leave the plate and move toward the terminal.
When initially charging a capacitor what happens on the negative side of the ciruit
Electrons at the negative terminal are repelled by it, so they leave and deposit on the plate connected to it
Describe the 1:1 interaction within the charging of a capacitor
For every electron removed from the positive plate an electron is deposited on the negative plate
How does a potential difference form on charging plates
One plate becomes positve and the other negative as electrons flow, creatinfg a uniform electric field between the plates
Why does the separation of charge beome harder over time
As charge builds up, the negative plate repels electrons more and the positive plate attracts them more, making further charge separation harder.
When has the capacitor stopped charging
When the capacitor’s potential difference equals the emf, the emf can no longer overcome the capacitor’s opposing pd, so charging stops.
In the scenario of overcoming the resistance to charge separation during charging a capacitor what does the pd between the plates represent
The work done per unit charge to move from one capacitor plate to the other
Why is an insulator used
To stop electrons flowing through the plates
What is the value of current in a charged capacitor
0A
Explain how a capacitor starts to discharge
A capacitor discharges once the emf source is removed, as only its own potential difference now drives the electrons.
State and explain how Q, I, V change as a capacitor charges
Q increases, because more charge is being separated to each plate
I decreases, because separating charge becomes harder so less charge will flow per unit time
V increases because separating charge becomes harder, so more work is done per unit charge to separate it
State and explain how Q, I, and V change as a capacitor discharges
Q decreases, as more electrons are released into the circuit and so less charge is separated
I decreases, because over time the potential difference decreases, so the driving force pushing electrons decreases
V decreases, as less charge is separated so the strength of the electric field between the plates decrease
What is the equation for capacitance in series
1/C = 1/C1 +1/C2
What is the equation for capacitance in parallel
C = C1 + C2 + …