complex number
written as a + bi
Add
(a + bi) + (c + di)
(a + c) + (b + d)i
Subtract
(a + bi) - (c + di)
= (a – c) + (b –d)i.
Multiply
(a + bi) (c + i)
FOIL Method
ac + ia +cbi +bi^2
Complex conjugate
z = a + bi
multiplicative identity
1 = 1 + 0i.
Multiplicative inverse
z = a + bi
Dividing complex numbers
(1) multiply by opposite of the denominator
(2) solve