1- ________ uses a continuous beam of X-rays to create images of the movement of internal structures that can be viewed on a monitor.
a. Radiography
b. Fluoroscopy
c. Digital radiography
d. All of the above
ANS: B - Fluoroscopy
Fluoroscopy uses a continuous beam of X-rays to create images of the movement of internal structures that can be viewed on a monitor.
2- __________ imaging is accomplished with fluoroscopy as opposed to radiography.
a. Static
b. Still
c. Dynamic
d. Colorized
ANS: C - Dynamic
Fluoroscopy allows imaging of anatomy in motion, or dynamic imaging.
3- Releasing the pressure applied to the ___________ will terminate the radiation exposure during fluoroscopy.
a. photocahtode
b. input phosphor
c. deadman switch
d. radiographic mode
ANS: C - deadman switch
Releasing the pressure applied to the deadman switch will terminate the radiation exposure during fluoroscopy.
4- The process that the exit radiation from the anatomic area of interest interacts with the input phosphor for conversion to visible light, which are converted to electrons by a photocathode, then focused by electrostatic focusing lenses, and accelerated toward an anode to strike the output phosphor is:
a. fluoroscopy
b. image intensification
c. deadman switch
d. radiographic mode
ANS: B - image intensification
Image intensification is the process that the exits radiation from the anatomic area of interest interacts with the input phosphor for conversion to visible light, which are converted to electrons by a photocathode, then focused by electrostatic focusing lenses, and accelerated toward an anode to strike the output phosphor.
5- Which of the following most accurately shows the energy sequence during image-intensified fluoroscopy?
a. Light to X-rays to electrons to light
b. X-rays to light to electrons to light
c. X-rays to electrons to light
d. Electrons to light to electrons
ANS: B - X-rays to light to electrons to light
X-rays exiting the patient interact with the image intensifier to produce light photons which are then converted to electrons and finally back to light energy.
6- The __________ is coated with light-emitting crystals to absorb electrons and emit light.
a. input phosphor
b. output phosphor
c. photocathode
d. accelerating anode
ANS: B - output phosphor
The output phosphor is coated with light-emitting crystals to absorb electrons and emit
7- The __________ consists of a light-emitting material (like cesium iodide) to absorb X-rays and emits light.
a. input phosphor
b. output phosphor
c. photocathode
d. accelerating anode
ANS: A - input phosphor
The input phosphor absorbs X-rays and emits light.
8- This part of the image intensifier absorbs light and converts light to electrons.
a. Input phosphor
b. Output phosphor
c. Photocathode
d. Electrostatic focusing lenses
ANS: C - Photocathode
The photocathode absorbs light and converts light to electrons.
9- The input phosphor is ________________ than the output phosphor.
a. larger
b. smaller
c. the same size as
d. brighter
ANS: A - larger
The input phosphor is considerably larger than the output phosphor.
10- The gain related to the decrease in size from the input to the output phosphor that increases the light intensities is the:
a. brightness gain
b. flux
c. minification gain
d. conversion factor
ANS: C - minification gain
The image at the output phosphor is brighter in part because it is significantly smaller than the same image at the input phosphor.
11- This is measured in cd/m²/mR/s.
a. Brightness gain
b. Flux
c. Minification gain
d. Conversion factor
ANS: D - Conversion factor
The conversion factor, another descriptor of the overall ability of an image intensifier to create a brighter image, is measured in cd/m²/mR/s.
12- The formula for brightness gain is:
a. brightness gain = minification gain − flux gain
b. brightness gain = minification gain/flux gain
c. brightness gain = minification gain × flux gain
d. brightness gain = minification gain + flux gain
ANS: C - brightness gain = minification gain × flux gain
Brightness gain = minification gain × flux gain.
13- The conversion factor is a(n) ______________ term for brightness gain and is typically about 1% of the brightness gain value.
a. older; 1%
b. older; 10%
c. newer; 1%
d. newer; 10%
ANS: C - newer; 1%
The conversion factor is a newer term for brightness gain and is typically about 1% of the brightness gain value.
14- In reference to image intensification, the function that adjusts and maintains the overall image brightness and contrast during the fluoroscopic procedure is:
a. DQE
b. APR
c. ABC
d. AEC
ANS: C - ABC
ABC, or automatic brightness control, maintains the brightness and contrast of the fluoroscopic image during the procedure.
15- When operated in magnification mode, the electrostatic lenses have __________ voltage.
a. decreased
b. increased
c. the same amount as usual
d. one half
ANS: B - increased
Magnification of the fluoroscopic image occurs when the electrostatic lenses have more voltage applied, creating a more negative charge.
16- The formula to determine the amount of magnification created when in magnification mode is:
a. MF = full size input phosphor / selected input phosphor
b. MF = full size input phosphor * selected input phosphor²
c. MF = selected input phosphor / full size input phosphor
d. MF = selected input phosphor² / full size input phosphor²
ANS: A - MF = full size input phosphor / selected input phosphor
The magnification factor during fluoroscopy is equal to the full size input phosphor divided by the selected input phosphor.
17- If a 30/23/15 cm image intensifier is operated in the 23 cm mode, the fluoroscopic image will be magnified by a factor of:
a. 1.3
b. 1.5
c. 1.7
d. 2
ANS: A - 1.3
Based on the formula, the MF = the full size of the input phosphor (30 cm) / the selected input phosphor size (23 cm).
18- Magnification of the fluoroscopic image results in improved:
a. brightness
b. spatial resolution
c. contrast
d. exposure
ANS: B - spatial resolution
Using the magnification mode improves spatial resolution of the fluoroscopic image.
19- A disadvantage of using magnification mode during fluoroscopy is:
a. the image has less resolution.
b. the image brightness is inconsistent.
c. the patient receives additional radiation dose.
d. none of the above.
ANS: C - the patient receives additional radiation dose.
Additional X-ray photons must leave the patient and be absorbed by the image intensifier when magnification mode is used, resulting in increased patient dose.
20- Typical fluoroscopic systems have spatial resolution capabilities in the range of:
a. 2 to 3 Lp/mm
b. 4 to 6 Lp/mm
c. 7 to 9 Lp/mm
d. 10 to 12 Lp/mm
ANS: B - 4 to 6 Lp/mm
Typical fluoroscopic systems have spatial resolution capabilities in the range of 4 to 6 Lp/mm.
21- In fluoroscopy, shape distortion is caused by:
a. angling the tube
b. angling the image intensifier
c. the curved shape of the photocathode
d. the position of the electrostatic focusing lenses
ANS: C - the curved shape of the photocathode
Shape distortion during fluoroscopy is the result of the curved shape of the input phosphor and photocathode.
22- Distortion of the fluoroscopic image that appears as unequal magnification is:
a. noise
b. pincushion appearance
c. vignetting
d. magnification
ANS: B - pincushion appearance
Pincushion appearance is the distortion of the fluoroscopic image that appears as unequal magnification.
23- A loss of brightness around the edge of the fluoroscopic image due to the curve of the photocathode is:
a. noise
b. pincushion appearance
c. vignetting
d. magnification
ANS: C - vignetting
Vignetting is the loss of brightness around the periphery of the fluoroscopic image.
24- Increasing the mA is the way to correct a fluoroscopic image that has:
a. noise
b. pincushion appearance
c. vignetting
d. magnification
ANS: A - noise
When a fluoroscopic image has noise, or is noisy, the quantity of radiation (mA) must be increased because the issue is too few photons being used to create the image.