a. the focal spot will be smaller.
b. the focal spot will be larger.
c. lower exposure factors can be used.
d. higher exposure factors can be used.
Solution: d. higher exposure factors can be used
When the stream of electrons constantly has a new area of the target to hit, the result is that higher exposure factors can be used.
REF: p.18
a. Glass
b. Paper
c. Metal
d. Lead
Solution: c. Metal
Metal envelopes are more commonly found in today’s x-ray tube, replacing glass envelopes.
REF: p.19
a. Decrease in off-focus radiation
b. Increase in off-focus radiation
c. Increased deposits of tungsten on the inside surface of the envelope
d. A and C
Solution: a. Decrease in off-focus radiation
The metal x-ray tube envelope results in less off-focus radiation being produced.
REF: p.20
a. oil
b. air
c. A and B
d. none of the above
Solution: d. none of the above
The x-ray tube envelope has been evacuated, leaving a vacuum present.
REF: p.20
a. the speed of light.
b. approximately one half the speed of light.
c. dependent on the mAs set.
d. dependent on the exposure time set.
Solution: b. approximately one half the speed of light
The electrons in the tube current travel at approximately one half the speed of light.
REF: p.20
a. 15 to 40 kVp.
b. 20 to 65 kVp.
c. 30 to 150 kVp.
d. 60 to 225 kVp.
Solution: c. 30 to 150 kVp
The kVp in the diagnostic x-ray range varies from approximately 30 to 150.
REF: p.20
a. 0
b. 15
c. 85
d. 100
Solution: d. 100
With a standard x-ray tube, 100% of the x-ray beam produced with 65 kVp is the result of bremsstrahlung interactions. The electrons must have at least 69.5 keV to produce characteristic radiation.
REF: p.20
a. 0
b. 15
c. 85
d. 100
Solution: c. 85
With a standard x-ray tube, 85% of the x-ray beam produced with 90 kVp is the result of bremsstrahlung interactions.
REF: p.20
a. 0
b. 15
c. 85
d. 100
Solution: a. 0
With a standard x-ray tube, 0% of the x-ray beam produced with 65 kVp is the result of characteristic interactions. The electrons must have at least 69.5 keV to produce characteristic radiation.
REF: p.21
a. 0
b. 15
c. 85
d. 100
Solution: b. 15
With a standard x-ray tube, 15% of the x-ray beam produced with 90 kVp is the result of characteristic interactions.
REF: p.21
a. kVp
b. mA
c. angstroms
d. keV
Solution d. keV
X-ray photon energy is measured in keV.
REF: p.22
a. monoenergetic spectrum.
b. x-ray emission spectrum.
c. gamma ray emission spectrum.
d. x-ray transmission spectrum.
Solution: b. x-ray emission spectrum
The x-ray beam is polyenergetic (has many energies) and consists of a wide range of energies known as the x-ray emission spectrum.
REF: p.22
a. 50 keV.
b. 75 keV.
c. 100 keV.
d. 125 keV.
Solution: c. 100 keV
In that the p in kVp stands for peak, the highest energy produced with a 100 kVp exposure is 100 keV.
REF: p.22
a. The anode begins to rotate.
b. Voltage is applied across the tube.
c. Current is applied to the filament.
d. A space charge is created.
Solution: b. Voltage is applied across the tube
Voltage is not applied across the tube until the exposure button has been pressed.
REF: p.24
a. 0.5 to 2 mA
b. 3 to 5 mA
c. 0.5 to 2 A
d. 3 to 5 A
Solution: d. 3 to 5 A
It takes about 3 to 5 A of current passing through the filament to produce enough thermionic emission to create a space charge.
REF: p.23
a. kinetic energy.
b. thermal energy.
c. electromagnetic energy.
d. A and C.
e. B and C.
Solution: e. B and C
The kinetic energy of the electrons is converted into thermal (heat) and electromagnetic (x-ray) energies.
REF: p.16
a. the number of photons.
b. the ability of the photons to penetrate.
c. the quantity of radiation.
d. whether or not the photons were made well.
Solution: b. the ability of the photons to penetrate
X-ray beam quality refers to the penetrability of the photons.
REF: p.26
a. doubling the tube current.
b. doubling the quantity of x-ray photons.
c. doubling the thermionic emission.
d. all of the above.
Solution: d. all of the above
Doubling the mA results in twice the thermionic emission, twice the tube current, and twice the number of x-ray photons produced.
REF: p.30
a. fewer x-ray photons.
b. more x-ray photons.
c. higher photon energy.
d. lower photon energy.
Solution: a. fewer x-ray photons
Fewer x-ray photons are produced when the exposure time is shortened.
REF: p.30
a. 4 mAs
b. 40 mAs
c. 400 mAs
d. 4000 mAs
Solution: b. 40 mAs
Since mAs is mA × exposure time, 400 mA × 0.100 s is equal to 40 mAs.
REF: p.30
a. 1; 99
b. 99; 1
c. 0; 100
d. 100; 0
e. 50; 50
Solution: b. 99; 1
Most of the electron kinetic energy in the tube current (>99%) is converted into heat, whereas less than 1% of it is converted into x-rays.
REF: p.24
a. larger the actual focal spot.
b. smaller the actual focal spot.
c. larger the effective focal spot.
d. smaller the effective focal spot.
Solution: c. larger the effective focal spot
Based on the line focus principle, the larger the anode angle, the larger the effective focal spot.
REF: p.33
a. 10%
b. 25%
c. 45%
d. 60%
Solution: c. 45%
The intensities between the anode and cathode ends of the x-ray field can vary as much as 45% due to the anode heel effect.
REF: p.34
a. lead
b. tungsten
c. glass
d. aluminum
Solution: d. aluminum
Added tube filtration is usually made of aluminum.
REF: p.35